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RUDIKE [14]
3 years ago
8

NEED AN ANSWER URGENTLY !!!

Chemistry
1 answer:
pshichka [43]3 years ago
6 0

I think the answer is D.

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What element has 28 electrons when electrically neutral
muminat

Answer:

nickel

It also tells you the number of electrons that the element has in its outside shells. If the atomic number of nickel is 28 then every atom of nickel has 28 protons in its nucleus and 28 electrons outside the nucleus.

Explanation:

5 0
3 years ago
An organic compound that contains a carbonyl group with a hydroxyl group attached to it is an example of a(n)
lawyer [7]
An organic compound that contains a carbonyl group with a hydroxyl group attached to it is an example of a (d) carboxylic acid.
8 0
3 years ago
Calculate the volume of 38.0 g of carbon dioxide at STP. Enter your answer in the box provided. L
Free_Kalibri [48]

Answer:

19.3 L

Explanation:

V= n × 22.4

where V is volume and n is moles

First, to find the moles of CO2, divide 38.0 by the molecular weight of CO2 which is 44.01

n= m/ MM

n= 38/ 44.01

n= 0.86344012724

V= 0.86344012724 × 22.4

V= 19.3410588502 L

V= 19.3 L

7 0
3 years ago
How many miles are in 215 grams of water
Irina18 [472]
You're off to a good start, now find the mass of H2O and put it under I mol,

then multiply 1 mol over the mass of H2O by 215 grams
3 0
3 years ago
Calculate the volume of the gas, in liters, if 1.75 mol has a pressure of 1.28 atm at a temperature of -7 ∘C
Alexandra [31]

Answer:

A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.

 

You need to apply the ideal gas law PV=nRT

 

You have the pressure, P=1.01 atm

you have the volume, V = 2.21 L

The ideal gas constant R= 0.08205 L. atm/ mole.K at  273 K

 

find n = PV/RT = (1.01 atm x 2.21 L / 0.08205 L.atm/ mole.K x 273 K)

 

n= 0.1 mole, Now find the pressure for n=0.1 mole, T= 299K and

L=1.23 L

 

P=nRT/V= 0.1mole x 0.08205 (L.atm/ mole.K x 299 k)/ 1.23 L

= 1.994 atm

Explanation:

6 0
3 years ago
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