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luda_lava [24]
3 years ago
13

Define nortons theorem​

Physics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

<em><u>In direct-current circuit theory, Norton's theorem is a simplification that can be applied to networks made of linear time-invariant resistances, voltage sources, and current sources. At a pair of terminals of the network, it can be replaced by a current source and a single resistor in parallel.</u></em>

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What is the critical angle for light going from crown glass to air?
GarryVolchara [31]

Answer:

The critical angle for a diamond in air is 24 degrees, while the critical angle for glass is 41 degrees.

Explanation:

Rays exiting the material at an angle less than the critical angle will be refracted, and rays incident on the interface at greater than the critical angle will be totally reflected back inside the material.

3 0
3 years ago
How much heat does it take to raise a<br> cup of water (2.34 x 10-4 m3) from<br> 15.0 °C to 75.0 °C?
Allisa [31]

Answer:58600

Explanation:

Trust me it’s correct.

8 0
3 years ago
Determine the kinetic of 600 kg roller coaster car that is moving with the speed of 35.2 m/s.
antiseptic1488 [7]
The answer is 10,560 Joules or 1.1*10^4


Explanation:

Step 1: Calculate
The equation for Kinetic Energy is

Kinetic energy=.5 times Mass times Velocity²
KE=.5*m*v²

so we plug in our numbers
KE=.5*600*35.2²

This works out to be 10,560 Joules or 1.1*10^4
5 0
3 years ago
When you put a book on a table the table pushes back. which newton law
sergeinik [125]
Newtons Third law of motion
6 0
4 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2  m v₀²

v = √2 v₀

6 0
3 years ago
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