Examples of carbohydrates: <span><span>glucose (monosaccharide) and </span><span>fructose (monosaccharide)
Examples of lipids: fats and steroids
Source credit:
</span></span>http://examples.yourdictionary.com/examples-of-lipids.html
https://www.thoughtco.com/examples-of-carbohydrates-603884
The Leaves it's B because to maintain photosynthesis it must be reached through the Leaved
Answer:
10 mol/kg.
Explanation:
Molality can be defined as the number of moles of solute divided by the mass of solvent.
Number of moles = mass/molar mass
= 25/25
= 1 mol.
Mass of solvent in kg = 100 g * 1 kg/1000 g
= 0.1 kg
Molality, m = 1/0.1
= 10 mol/kg.
If the humidity is high enough we may notice fumes rising out of the mixture containing Br solution. The fumes produced are HBr fumes.
<h3>
What is hydrogen bromide? </h3>
Hydrogen bromide (HBr) is a corrosive and toxic gas. It can be fatal if it is inhaled. It is very corrosive to our respiratory system, to our eyes, and when it is in contact with skin. When it is in mist form or in a liquid form it will cause burns to all tissue if it falls upon.
<h3>Why fumes are produced? </h3>
Hydrogen Bromide is a highly irritating, corrosive, nonflammable gas having a pungent odor at room temperature. It will fume in air which have high humidity because formation of hydrobromic acid takes place; it is the diatomic molecule.
Under ordinary conditions hydrogen bromide is a gas but it can be converted into liquid. Hydrobromic acid is then formed after hydrogen bromide is dissolved in water.
Thus we concluded that the fumes produced when bromine solution is in contact with moist air is HBr fumes.
learn more about HBr:
brainly.com/question/2712747
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<u>Given:</u>
Enthalpy change (ΔH) for SO3 decomposition = +790 kJ
Moles of SO3 = 2.1 moles
<u>To determine:</u>
Energy required when 2.1 moles of SO3 reacts
<u>Explanation:</u>
The decomposition reaction is -
2SO3(g) → 2S(s) + 3O2 (g)
Energy required when 2 moles of SO3 reacts is 790 kJ
Thus, for 2.1 moles of SO3 the energy requirement would be
= 2.1 moles SO3 * 790 kJ/2 moles SO3 = 829.5 kJ
Ans: 830 kJ are required when 2.1 moles of SO3 reacts.