When a balloon containing 635 mL of air is taken from sea level (at standard pressure) to a higher altitude, the balloon expands
to 829 mL. What is the air pressure at this new altitude (in atm)?
1 answer:
Answer:
0.766atm
Explanation:
Boyles law
P1V1=P2V2
1×635=P2×829
P2=635/829
P2=0.766atm
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