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Vikentia [17]
3 years ago
8

Two streams merge to form a river. One stream has a width of 8.9 m, depth of 3.8 m, and current speed of 2.3 m/s. The other stre

am is 6.5 m wide and 3.9 m deep, and flows at 2.6 m/s. If the river has width 10.7 m and speed 3.0 m/s, what is its depth?
Physics
1 answer:
SpyIntel [72]3 years ago
7 0
<h2>Depth of river is 4.48 m</h2>

Explanation:

Discharge = Area x Velocity

Discharge of river = Discharge of stream 1 + Discharge of stream 2

A_rv_r=A_1v_1+A_2v_2

Area of stream 1 = w₁ x d₁ = 8.9 x 3.8 = 33.82 m²

Area of stream 2 = w₂ x d₂ = 6.5 x 3.9 = 25.35 m²

Velocity of stream 1 = 2.3 m/s

Velocity of stream 2 = 2.6 m/s

Velocity of river = 3 m/s

\texttt{Area of river = }w_r\times d_r=10.7\times d_r

Substituting

             A_rv_r=A_1v_1+A_2v_2\\\\10.7\times d_r\times 3=33.82\times 2.3+25.35\times 2.6\\\\d_r=4.48m

Depth of river = 4.48 m

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Answer:

F = 4.147 × 10^23

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Explanation:

Given the following :

mass of Jupiter (m1) = 1.9 × 10^27

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Gravitational force (F) :

(Gm1m2) / r^2

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F = [(6.673×10^-11) × (1.9 × 10^27) × (1.99 × 10^30)] / (7.8 × 10^11)^2

F = [25.231 × 10^(-11+27+30)] / (60.84 × 10^22)

F = (25.231 × 10^46) / (60.84 × 10^22)

F = 3.235 × 10^(46 - 22)

F = 0.4147 × 10^24

F = 4.147 × 10^23

Speed of Jupiter (v) :

v = √(Fr) / m1

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v = √32.3466 × 10^(23+11) / 1.9 × 10^27

v = √32.3466× 10^34 / 1.9 × 10^27

v = √17. 023 × 10^34-27

v = √17.023 × 10^7

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A proton, an alpha particle (a bare helium nucleus), and a singly ionized helium atom are accelerated through a potential differ
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