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coldgirl [10]
3 years ago
6

Nuclear power plants have the greatest environmental impact during __________. A) operation B) mining C) waste disposal D) const

ruction E) none of the above
Chemistry
2 answers:
oksian1 [2.3K]3 years ago
7 0
I believe is C) waste disposal
lyudmila [28]3 years ago
5 0
The correct option is C.
The issue of disposal of waste of nuclear power plants has been a controversial issue for long because of the hazardous effects which these wastes have on human health and the environment. Most of the waste are usually long lived radioactive wastes which can remain active for a very long time and which have detrimental effect on both the environment and the human health.<span />
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How reactive is an atom of Sodium(Na) and why? A)Sodium (Na) is very reactive because it does not have enough protons in the nuc
padilas [110]
A. hope this helps ok god speed

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4 years ago
Which of the following substances is classified as a solution?
Ainat [17]

Answer:

Salt water

Explanation:

Please mark me brainliest and thank me.

3 0
3 years ago
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An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
List three properties if the elements that are useful in sorting the elements.
m_a_m_a [10]
Mass, what its made out of, and atomic number
5 0
3 years ago
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When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electr
poizon [28]

Answer:

n = 3

Explanation:

Given the formula for the transition energy of an atom with 1 electron:

E=-13.6*Z^{2}*(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}} ) eV

For the H transition n=5 to n=2:

E=-13.6*(\frac{1}{4}-\frac{1}{25} ) eV=-2.856 eV

Then we solve for nf with Z=2 (Helium)

n_{f}=\sqrt{\frac{n_{i}^{2}*Z^{2}*13.6 eV }{2.856eV*n_{i}^{2}+13.6eV*Z^{2}} }

n_{f}=\sqrt{\frac{4^{2}*2^{2}*13.6 eV }{2.856eV*4^{2}+13.6eV*2^{2}} }=3

Is near 3, actually the energy of the transitions are:

H (5⇒2) = -2.85 eV = 434 nm (Dark blue)

He (4⇒3) = -2.64 eV = 469 nm (Light blue)

I thought it was cool to see the actual colors. Included them.

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3 years ago
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