1. Decomposition reaction,2. Skeletal equation,3. -,nonmetal,4. Combination,double displacement reaction,5. Neutralization,6. Aqueous solution, precipitate,7. Reactants,products,law of conservation of mass,8. Co2 gas,water vapors,9. Atomic,molecular masses . Tried my best . Mark brainliest
There are 618.68 g in 4.5 moles of NaF.
The total number of moles of any substance equals the ratio of its given mass in a chemical reaction to the mass of one mole or molar mass of that substance.
It is known that one mole of NaF or molar mass of NaF is 41.98 g/mol.
Given that number of moles is 4.5 moles.
Therefore, calculate the mass of NaF in grams as follows.
No. of moles = Given mass / Molar mass
mass in grams = No. of moles × Molar mass
= 4.5moles × 41.98 g/mol
= 188.91 g
Hence, we can conclude that there are 188.91 g in 4.5 moles of NaF.
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Answer:
pH of the final solution = 9.15
Explanation:
Equation of the reaction: HCl + NH₃ ----> NH₄Cl
Number of moles of NH₃ = molarity * volume (L)
= 0.4 M * (300/1000) * 1 L = 0.12 moles
Number of moles of HCl = molarity * volume (L)
= 0.3 M * (175/1000) * 1 L = 0.0525 moles
Since all he acid is used up in the reaction, number of moles of acid used up equals number of moles of NH₄Cl produced
Number moles of NH₄Cl produced = 0.0525 moles
Number of moles of base left unreacted = 0.12 - 0.0525 = 0.0675
pOH = pKb + log([salt]/[base])
pKb = -logKb
pOH = -log (1.8 * 10⁻⁵) + log (0.0525/0.06755)
pOh = 4.744 + 0.109
pOH = 4.853
pH = 14 - pOH
pH = 14 - 4.853
pH = 9.15
Therefore, pH of the final solution = 9.15
Answer:
(1) Chloroplast
Explanation:
Cells of living organisms are made up of certain function-specific structures called ORGANELLES. Some organelles are present in plant cells and absent in animal cells and vice versa. In a plant cell, one notable organelle that allows it perform the photosynthetic process is the CHLOROPLAST.
However, the chloroplast is predominantly found in the LEAF part of a plant. This is because leaf cells are the site of photosynthesis. Hence, according to this question, Joe would be able to tell whether the plant cell was from the leaf or the root by looking for CHLOROPLAST as a differentiating factor in each cell.