Question The quotient of a number and 5 has a result of 2. What is the number

chubhunter [2.5K]

The fourth choice. For example, (x+2)(x-2)>0 we'll get x>2 or x<-2 because whenever you substitute x>2 for example x = 3, the value will be higher than 0 itself.

If we substitute x = 3 (for x>2)

We'll get (3+2)(3-2)>0

5(1)>0

5>0 The statement is true.

If we substitute x = -3 (for x<-2)

We'll get (-3+2)(-3-2)>0

-1(-5)>0

5>0 The statement is true.

We don't say x>2 AND x<-2, In math, we only say x>2 OR x<-2

6 0

3 years ago

Read 2 more answers

A $78.00 pair of shoes cost $84.63 after tax is added. What

Evgen [1.6K]

6.63 is the answer barbz

8 0

3 years ago

Find the distance between the pair of coordinates: (-4, -3) and (-8, 7). A 10.77 B 3.74 C 04 D 12.65 Question

kenny6666 [7]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-8 - (-4)]^2 + [7 - (-3)]^2}\implies d=\sqrt{(-8+4)^2 + (7+3)^2} \\\\\\ d=\sqrt{(-4)^2 + 10^2}\implies d=\sqrt{116}\implies d\approx 10.77$

6 0

2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

The price of the product decreased by 10%and then decreased by 20% . calculate total percentage change between the final and ini

aev [14]

What is percentage change?

By quantifying the difference between two numbers and expressing it as an increase or decrease, the Percentage Change Calculator (percent change calculator) may determine the percentage change.

The initial price $V_{1}$ (100%) was decreased by 10%., then this reduced price is reduced more by 20% that becomes the final price $V_{2}$ which is 72.