Question

At a temperature of -25 °C, a sample of gas in a rigid container exerts a pressure of 55.8 kPa. At what temperature will the pressure reach 145 kPa?

Answer 1

Given:

$P_{1} = \text{55.8 kPa}$

$T_{1} = -25^{\circ}\text{C + 273 = 248 K}$

$P_{2} = \text{145 kPa}$

Unknown:

$T_{2}$

Solution:

$\dfrac{P_{1}}{T_{1}} = \dfrac{P_{2}}{T_{2}}$

$T_{2} = T_{1} \times \dfrac{P_{2}}{P_{1}}$

$T_{2} = \text{248 K} \times \dfrac{\text{145 kPa}}{\text{55.8 kPa}}$

$\boxed{T_{2} = \text{644 K}}$