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Fudgin [204]
3 years ago
12

Whats a Natural Selection?

Chemistry
2 answers:
Nastasia [14]3 years ago
7 0

Answer:

Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations.

Explanation:

I hope this helps :) Thank you. Plz mark brainliest.

BigorU [14]3 years ago
4 0
Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations.
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Usually the controlled experiment is the one that is not tested so they look at the experimental experiment to find the differences. Sorry if this doesn't answer your question.
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The movement of electrons causes:
ki77a [65]
Your answer is B ;) the movement of electrons cause electrical energy :)


4 0
3 years ago
Question 2 (1 point)<br> Al + S8 = Al2S3<br> When balanced, what is the coefficient of Al?
gtnhenbr [62]

Answer:

16

Explanation:

FIRST AND FOREMOST, BALANCE YOUR EQUATION.

Al + S8 ➡️ Al2S3

Numbers of Al=1. ➡️ Numbers of Al = 2

Numbers of S =8. ➡️ Numbers of S. = 3

USE COEFFICIENT TO BALANCE THE EQUATION.

16Al + 3S8 ➡️ 8Al2S3

Now the Numbers of Al and S in both sides of eqn. is balanced

The Answer Is 16

3 0
3 years ago
Read 2 more answers
What is the formula for potassium sulfide? <br> a. k2s2 <br> b. k2s <br> c. ks <br> d. ks2
wlad13 [49]
The formula for potassium sulfide is K2S
4 0
4 years ago
Read 2 more answers
The compound 1,1-difluoroethane decomposes at elevated temperatures to give fluoroethylene and hydrogen fluoride: CH3CHF2(g) → C
Maru [420]

Answer : The final temperature would be, 791.1 K

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 460^oC = 5.8\times 10^{-6}s^{-1}

K_2 = rate constant at T_2 = 4\times K_1

Ea = activation energy for the reaction = 265 kJ/mol = 265000 J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 460^oC=273+460=733K

T_2 = final temperature = ?

Now put all the given values in this formula, we get:

\log (\frac{4\times K_1}{K_1})=\frac{265000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{733K}-\frac{1}{T_2}]

T_2=791.1K

Therefore, the final temperature would be, 791.1 K

4 0
3 years ago
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