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Greeley [361]
3 years ago
6

The statement that "the lowest energy configuration for an atom is theone having the maximum number of unpaired electrons allowe

d by thePauli principle in a particular set of degenerate orbitals" is known asa. Pauli Exclusion Princpleb. Hund's rulec. Heisenberg's uncertainty principled. Aufbau principle
Physics
1 answer:
Mila [183]3 years ago
3 0

Answer:

"The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by thePauli principle in a particular set of degenerate orbitals" is known as Hund's rule.

Explanation:

Pauli's Exclusion principle states that "two or more electrons can not have the same values of the set of all quantum numbers in an atom or a molecule".

So, the given statement <em>is not</em> Pauli's Exclusion principle.

Hund's rule states that the lowest energy configuration of an atom is that one in which the maximum number of parallel spins of the electrons are present.

The given statement is "The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by the Pauli principle in a particular set of degenerate orbitals", which is same as the Hund's rule.

Thus, the given statement is Hund' rule.

Heisenberg's uncertainty principle states that the momentum and position of an object can not be measured exactly at the same time.

So, the given statement <em>is not</em> Heisenberg's uncertainty principle.

Aufbau principle tells about the filling of the electrons in subshells of an atom. Therefore, the given statement <em>is not </em>Aufbau principle.

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Answer:

Part a)

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Part b)

\theta = -137.7 degree

Part c)

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Explanation:

As we know that acceleration is rate of change in velocity of the object

So here we know that

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Part a)

differentiate x and y two times with respect to time to find the acceleration

a_x = \frac{d^2}{dt^2}(-19 + t - 3t^3)

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a_x = -18t

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a_y = \frac{d}{dt}(0 +7 - 18t)

a_y = -18

Now the acceleration of the object is given as

\vec a = (-18t)\hat i + (-18)\hat j

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\vec a = -19.8 \hat i - 18 \hat j

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\vec F = m\vec a

\vec F = (0.29 kg)(-19.8 \hat i - 18 \hat j)

\vec F = -5.74 \hat i - 5.22 \hat j

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Part b)

Direction of the force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{-5.22}{-5.74}

\theta = -137.7 degree

Part c)

For velocity of the particle we have

v_x = \frac{dx}[dt}

v_x = (0 +1 - 9t^2)

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now at t = 1.1 s

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now the direction of the velocity is given as

\theta = tan^{-1}(\frac{v_y}{v_x})

\theta = tan^{-1}(\frac{-12.8}{-9.89})

\theta = -127.7 degree

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