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Greeley [361]
3 years ago
6

The statement that "the lowest energy configuration for an atom is theone having the maximum number of unpaired electrons allowe

d by thePauli principle in a particular set of degenerate orbitals" is known asa. Pauli Exclusion Princpleb. Hund's rulec. Heisenberg's uncertainty principled. Aufbau principle
Physics
1 answer:
Mila [183]3 years ago
3 0

Answer:

"The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by thePauli principle in a particular set of degenerate orbitals" is known as Hund's rule.

Explanation:

Pauli's Exclusion principle states that "two or more electrons can not have the same values of the set of all quantum numbers in an atom or a molecule".

So, the given statement <em>is not</em> Pauli's Exclusion principle.

Hund's rule states that the lowest energy configuration of an atom is that one in which the maximum number of parallel spins of the electrons are present.

The given statement is "The lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by the Pauli principle in a particular set of degenerate orbitals", which is same as the Hund's rule.

Thus, the given statement is Hund' rule.

Heisenberg's uncertainty principle states that the momentum and position of an object can not be measured exactly at the same time.

So, the given statement <em>is not</em> Heisenberg's uncertainty principle.

Aufbau principle tells about the filling of the electrons in subshells of an atom. Therefore, the given statement <em>is not </em>Aufbau principle.

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In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48
cluponka [151]

Answer:

The thickness is  \Delta y =  2.4 *10^{-6} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda  = 480 \ nm = 480*10^{-9} \  m

    The first order of the dark  fringe is  m_1 =  16

     The second order of dark fringe considered is  m_2 = 6

Generally the condition for destructive interference is mathematically represented as

        y = \frac{m \lambda}{2}

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

      y_1 - y_2 = \Delta y =  \frac{m_1 \lambda}{2} -  \frac{m_2 \lambda}{2}

=>  y_1 - y_2 = \Delta y =  \frac{16 *480*10^{-9}}{2} -  \frac{6 *480*10^{-9}}{2}

=>  y_1 - y_2 = \Delta y =  5 (480*10^{-9})

=>  \Delta y =  2.4 *10^{-6} \  m

8 0
3 years ago
A mixture of helium and oxygen is used in scuba diving tanks to help prevent ""the bends"". 46 L helium and 12 L oxygen are comb
marin [14]

Answer

given,

For helium

Volume,V = 46 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₁ = ?

number of moles

we know

P V = n R T

n_1 =\dfrac{46 \times 1}{0.0821\times 298}

  n₁ = 1.89 moles

For oxygen

Volume,V = 12 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₂ = ?

number of moles

we know

P V = n R T

n_2 =\dfrac{12 \times 1}{0.0821\times 298}

  n₂ = 0.49 moles

Total volume of tank = 5 L

temperature of tank = 298 K

Partial pressure of helium

P_1=\dfrac{n_1 R T}{V}

P_1=\dfrac{1.89\times 0.0821\times 298}{5}

     P₁ = 9.25 atm

Partial pressure of oxygen

P_2=\dfrac{n_2 R T}{V}

P_2=\dfrac{0.49\times 0.0821\times 298}{5}

    P₂ = 2.39 atm

total pressure

    P = P₁ + P₂

    P = 9.25 + 2.39

    P = 11.64 atm

8 0
2 years ago
What is the amount of displacement of a runner who runs exactly 2 laps around a 400 meter track?
max2010maxim [7]

At the end of the laps, the runner's displacement is zero.

8 0
3 years ago
This table shows four examples of experiments.
yarga [219]

Answer

32000

Explanation:

120394

5 0
3 years ago
Read 2 more answers
What is the acceleration of a 10 kg mass pushed 5 n forceushed by a 5n(kg-m/s2) (use gresa method)
Pepsi [2]

In this problem,

Applied force(F) = 10 N

The object’s mass (m) is 5 kg.

Having said that,

An object’s force is equal to the product of its mass and the acceleration it experiences as a result of the applied force.

i.e., Mass + Acceleration = Force (a)

F= m×a

Therefore,

A= F÷m

A= (10÷5) m/sec²

A= 2 m/sec²

Consequently, the object’s acceleration,

A=2 m/sec²

Concept of force and acceleration:

This states that the rate of velocity change of an object is directly proportional to the applied force and moves in the direction of the applied force.

It can be expressed mathematically as force (N) = mass (kg) x acceleration (m/s2). Therefore, an object with constant mass will accelerate in direct proportion to the applied force.

To know more about such problems, visit:

brainly.com/question/16743612

#SPJ4

6 0
1 year ago
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