Activity 1 MATCH IT

If kinetic energy is tripled what happens to centripetal acceleration.

Bas_tet [7]

Answer:

Triples

Explanation:

Kinetic energy =1/2 mv^2 + 1/2 Iw^2

v= linear velocity

w= angular velocity

I= moment of inertia of object

I = k mr^2 where k is a constant for a particular shaped object

v = rw

w=v/r

Rotational Kinetic energy = 1/2 k m× (v/r)^2 × r^2

Total Kinetic energy = translational Kinetic energy + rotational Kinetic energy

KE = 1/2 (1+k) mv^2

Centripetal acceleration = mv^2/r

When KE is tripled, because 1/2(1+k) is a constant for a particular object, mv^2 part gets tripled. r doesn't appear in the equation of total Kinetic energy. So tripling Kinetic energy doesn't affect r. Therefore centripetal acceleration also gets tripled.

6 0

3 years ago

In the nuclear fission process mass is converted into energy. Determine the total mass that must be converted to energy in one y

brilliants [131]

Answer:

1) Mass that needs to be converted at 100% efficiency is 0.3504 kg

2) Mass that needs to be converted at 30% efficiency is 1.168 kg

Explanation:

By the principle of mass energy equivalence we have

$E=mc^{2}$

where,

'E' is the energy produced

'm' is the mass consumed

'c' is the velocity of light in free space

Now the energy produced by the reactor in 1 year equals

$Energy=Power\times time\\\\\therefore Energy=1\times 10^{9}\times 365\times 24\times 3600\\\\Energy=31.536\times 10^{15}Joules$

Thus the mass that is covertred at 100% efficiency is

$mass=\frac{Energy}{c^{2}}\\\\mass=\frac{31.536\times 10^{15}}{(3\times 10^{8})^{2}}\\\\mass=\frac{31.536\times 10^{15}}{9\times 10^{16}}\\\\\therefore mass=0.3504kg$

Part 2)

At 30% efficiency the mass converted equals

$mass|_{30}=\frac{mass|_{100}}{0.3}\\\\mass|_{30}=\frac{0.3504}{0.3}\\\\mass|_{30}=1.168kg$

8 0

4 years ago

How much Power does a truck use to complete 4,100 J of Work in 30<br> seconds? *

alexandr1967 [171]

Answer:

136.67 watts

Explanation:

P=W/t

P=4100/30

P= 136.67 watts

7 0

3 years ago

Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod

aivan3 [116]

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force= $\frac{Gm_{1}m_{2} }{r^{2}}$

Coulombs's Law= $\frac{Kq_{1}q_{2} }{r^{2}}$

6 0

4 years ago

Read 2 more answers

A 4-kilogram cat is resting on top of a bookshelf that is 3 meters high. What is the cat’s gravitational potential energy relati

hichkok12 [17]

The answer is 117.6 J

The potential energy of the object is actually its stored energy:

<span>E = m · g · h
E - the potential energy of the object,
m - the mass of the object,
g - acceleration due to gravity,
h - the height of the object.

m = 4 kg
g = 9.8 m/s</span>²
h = 3 m

E = 4 * 9.8 * 3 = 117.6 J

4 0

3 years ago