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Mila [183]
3 years ago
10

Activity 1 MATCH IT

Physics
1 answer:
exis [7]3 years ago
4 0

Answer:

1. A hiking

2. C

3. B

4. D

5. E

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A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma
Bad White [126]

Length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

5 = emf/ (0.25 T× 0.25 m)

emf = 0.3125 v

Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

To learn more about the magnetic field refer here:

brainly.com/question/23096032

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5 0
2 years ago
When an object is in a gravitational field, it has energy in its __________ __________ energy store.what’s is the word in the mi
lisabon 2012 [21]

Answer:

I don't know if this is right or not but I think its Potential Energy

Explanation:

8 0
3 years ago
Identify three situations in which convection occurs.
Minchanka [31]
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
3 0
3 years ago
Read 2 more answers
a bicycle accelerates at 1 m/s² from an initial velocity of 4 m/s² for 10s. Find the distance moved by it during this interval o
BaLLatris [955]

Answer:

90 m

Explanation:

Acceleration, a=\frac {v-u}{t} where v and u are final and initial velocities respectively, t is the time taken

Substituting 1 m/s^{2} for a,  4 m/s for u and 10 s for t then

1*10=v-4

v=14 m/s

From kinematic equations

v^{2}=u^{2}+2as

Making s the subject then

s=\frac {v^{2}-u^{2}}{2a}=\frac {14^{2}-4^{2}}{2\times 1}=90 m

6 0
3 years ago
A 50-kg toboggan is coasting on level snow. As it passes beneath a bridge, a 20-kg parcel is dropped straight down and lands in
timama [110]

Answer:

KE2/KE1=0.71

Explanation:

By conservation of the linear momentum:

m1*V1 = (m1+m2)*V2

Solving for V2:

V2 = \frac{m1}{m1+m2}*V1

The kinetic energies are:

KE1=1/2*m1*V1^2

KE2 = 1/2*(m1+m2)*V2^2

KE2 = 1/2*(m1+m2)*(\frac{m1}{m1+m2}*V1)^2

Simplifying:

KE2 = 1/2*\frac{m1^2}{m1+m2}*V1^2

The ratio will be:

KE2/KE1=\frac{1/2*\frac{m1^2}{m1+m2}*V1^2}{1/2*m1*V1^2} =\frac{m1}{m1+m2}

KE2/KE1=0.71

5 0
3 years ago
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