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3 years ago

How would planting trees and grass on a hillside help protect the land from these processes?

Physics

1 answer:

Arada [10]3 years ago

3 0

Planting trees and grass on a hillside keeps the dirt and soil compacted so nothing fall.

I really do hope that this helps. ^_^

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A house at the bottom of a hill is fed by a full tank of water 5m deep and connected to the house by a pipe that is 110m long at

yawa3891 [41]

Answer:

a) $p=964178.7\ Pa$

b) $h=98.2853\ m$

Explanation:

Given;

depth of the water-tank, $d=5\ m$

length of the pipe, $l=110\ m$

inclination of the pipe from the horizontal, $\theta =58^{\circ}$

Now the effective vertical height of the water column from the free surface of the water to the bottom of the pipe at house:

$h=d+l.\sin\theta$

$h=5+110\sin58$

$h=98.2853\ m$

Now the pressure due to effective water head:

$p=\rho.g.h$

where:

$\rho=$ density of the liquid, here water

$g=$ acceleration due to gravity

$h=$ height of the liquid column

$p=1000\times9.81\times 98.2853$

$p=964178.7\ Pa$

Now the height of water corresponding to this pressure will be the same as the effective water head by the law of conservation of energy.

$h=98.2853\ m$

6 0

3 years ago

ASTRONOMY section

lozanna [386]

Answer:
I think it would be D stars

5 0

3 years ago

A racecar driver is driving her car down the drag strip at 120 m/s. What is the shortest distance in which she can brake and sto

DaniilM [7]

Answer:

1034.78 m

Explanation:

The shortest distance is the displacement of the car from initial position to final position.

Displacement of body is given using Newton's equations of motion.

Given:

Initial velocity, $u = 120$ m/s

Final velocity, $v = 0$ m/s( As the car stops in its final position)

Coefficient of static friction, $\mu=0.71$

Acceleration due to gravity, $g=9.8\textrm{ } m/s^{2}$

Now, when brakes are applied, only friction acts on the body in a direction opposite to that of its motion.

The acceleration of the car when friction acts the stopping force is given as:

$a=- \mu g$ .

The acceleration is negative as it reduces the velocity of the motion and acts in the direction opposite to that of the motion.

Plug in 0.71 for $\mu$ and 9.8 m/s² for $g$ . Solve for $a$ .

So, $a=-0.71\times 9.8=-6.958\textrm{ }m/s^{2}$ .

Now, displacement of the car is given using the following equation of motion:

$v^{2}=u^{2} +2aS$

Here, $S$ is the displacement of the racing car.

Plug in 120 m/s for $u$ , 0 m/s for $v$ , -6.958 m/s² for $a$ . Solve for $S$ . This gives,

$0^{2} =(120)^{2}+2(-6.958)S\\13.916S=14400\\S=\frac{14400}{13.916}=1034.78\textrm{ m}$

Therefore, the shortest distance in which she can brake and stop is 1034.78 m.

5 0

4 years ago

Read 2 more answers

Which of the following is a characteristic of active transport? Check all answers that apply.

vlada-n [284]

B. It moves substances against a concentration gradient. It requires energy from the cell to.

Hope this helps :)

5 0

4 years ago

Read 2 more answers

Two identical 0.50-kg carts, each 0.10 m long, are at rest on a low-friction track and are connected by a spring that is initial

Keith_Richards [23]

Answer:

The system's kinetic energy changes by 3.6 J

Explanation:

The given parameters are;

The number of cart = 2

The mass of each cart = 0.5kg

The initial length of the spring = 0.50 m

The final length of the spring =T0.3 m

The change in position of the first cart = 0.6 m

The energy given to the first cart = Work done by the force = Force × Displacement

The initial kinetic energy of the two cart moving together = Energy given to the first cart = 6.0 × 0.2 = 1.2J

The kinetic energy given to the two cart combined = The applied force × The total displacement of the two cart as they move together

The kinetic energy given to the two cart combined = 6.0 × (0.6 - 0.2)

The kinetic energy given to the two cart combined = 6.0 × 0.4 = 2.4 J

The total kinetic energy given to the two cart = 1.2 + 2.4 = 3.6 J

The total kinetic energy given to the two cart = 3.6 J

The system's kinetic energy changes by 3.6 J.

8 0

3 years ago