Answer:

Explanation:
F = Shearing force = 420 N
= Initial length = 2.6 cm
d = Diameter = 3.6 cm
r = Radius = 
E = Young's modulus = 
A = Area = 
Change in length is given by

The shear deformation of the vertebra is 
Answer:
The the quality of the refrigerant at the exit of the expansion valve is 0.179.
Explanation:
Given that,
Initial pressure = 10 bar
Temperature = 22°C
Final pressure = 2.0 bar
We using the value of h

The refrigerant during expansion undergoes a throttling process
Therefore, 
We need to calculate the quality of the refrigerant at the exit of the expansion valve
At 2.0 bar,
The property of ammonia


Using formula

Put the value into the formula



Hence, The the quality of the refrigerant at the exit of the expansion valve is 0.179.
The answer is no, the static charge would still be there.
The solution for this is:
Power = Energy transferred / Time taken
Energy Transferred in one second ( Power) = mgh/s
= (1.2x10^6)(9.8)(50) = 588000000 J/s
Power = 588000000 W
Or
Power is work done / time
Work done in one second = [ rate of fall of mass]
gh = 1.2* *9.81*50 x 10^6 J/s
= 5.886e+8 W