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Vladimir79 [104]
3 years ago
10

Enunciado: Una bola se lanza verticalmente de la parte superior de un edificio con una velocidad inicial de 25 m/s. La bola impa

cta al suelo en la base del edificio 7 segundos después de ser lanzada. (Marque la respuesta correcta)
¿Qué altura subió la bola (medida desde la parte superior del edificio)? a) 19.6 m b) 12.75 m c) 31.88 m d) 40 m e) 20 m
Physics
1 answer:
bearhunter [10]3 years ago
7 0

Responder:

Explicación:

Usaremos la ecuación de movimiento para determinar la altura de la bola medida desde la parte superior del edificio.

Usando la ecuación para obtener la altura de caída

S = ut + 1 / 2gt²

u es la velocidad inicial = 25 m / s

g es la aceleración debida a la gravedad = 9,81 m / s²

t es el tiempo = 7 segundos

S es la altura de la caída

S = 25 (7) +1/2 (9,81) × 7²

S = 175 + 4,905 (49)

S = 175 + 240,345

S = 415,35 m

Esto significa que la pelota se elevó a 415,35 m de altura

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Answer:

W = 0.842 J

Explanation:

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In this case the kinetic energy at point A is zero since the system is stopped

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now let's use conservation of energy

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so at the height is

            h = L - L cos 35

            h = L (1-cos 35)

we substitute

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we substitute in equation 1

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let's calculate

           W = 0.500 9.8 0.950 (1 - cos 35)

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Answer:

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7 0
3 years ago
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