Answer:
- <u><em>Displacement</em></u>
Explanation:
To describe the<em> change in position</em> you need to indicate the distance between the final and initial positions and the direction in which you moved. The distance is the magnitude.
The quantities that need both magnitude and direction to be described are named <em>vector quantities</em> or, just, vectors.
<em>The vector quantity that defines both the distance and direction between two positions </em>describes the <em>change in your position</em> and is named displacement. For instance, to indicate how you can goe to the supermarket from your house you cannot just say walk 2 miles. You need to indicate the direction; let's say 2 miles North. In this case, the displacement when you goe from your house to the supermarket is 2 miles North. And it is different of the displacement when you comeback from the supermarket to your house, because it would be 2 miles South.
1. D, constant
Force must be in the direction of the velocity to change speed.
2. B. to the center of the curvature
This allows the vehicle to complete the turn.
Answer:
Change in Velocity because
![at = v](https://tex.z-dn.net/?f=at%20%3D%20v)
Explanation:
Remeber area is length times Width. In this case, the area under a accleraton vs time graph is Accleration Times Time. Which is velocity
<h2>The acceleration of car is 0.2 ms⁻²</h2>
Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t +
a t²
In this question u = 0 , because car was at rest initially
Thus S =
a t²
here S is displacement and a is the acceleration of car
Therefore 360 =
a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a = ![\frac{360x2}{3600}](https://tex.z-dn.net/?f=%5Cfrac%7B360x2%7D%7B3600%7D)
or a = 0.2 m s⁻²
here we will use the momentum conservation
initial total momentum = final total momentum
![P_i = P_f](https://tex.z-dn.net/?f=P_i%20%3D%20P_f)
![m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}](https://tex.z-dn.net/?f=m_1v_%7B1i%7D%20%2B%20m_2v_%7B2i%7D%20%3D%20m_1v_%7B1f%7D%20%2B%20m_2v_%7B2f%7D)
now plug in all data here
![m(0) + 50m(8.1) = mv + 50mv](https://tex.z-dn.net/?f=m%280%29%20%2B%2050m%288.1%29%20%3D%20mv%20%2B%2050mv)
![405 = 51 v](https://tex.z-dn.net/?f=405%20%3D%2051%20v)
![v = 7.94 m/s](https://tex.z-dn.net/?f=v%20%3D%207.94%20m%2Fs)
so the final speed will be 7.94 m/s