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algol13
3 years ago
13

Three chairs were rolling across a flat office floor. The blue and red chairs are the same mass, and they have more mass than th

e yellow chair. Each chair was hit by another chair, but not from the same direction. Use the information in the diagram to answer.
Which chair(s) experienced the strongest force when hit? How do you know?


a
The blue and red chairs experienced the strongest force because they are both more massive than the yellow chair and they changed speed by the same amount.

b
The red chair experienced the strongest force because it is as massive as the blue chair and has the highest ending speed.

c
All three chairs experienced the same force because they changed speed by the same amount.

d
The blue chair experienced the strongest force because it takes more force to slow an object than it takes to make it go faster.

Physics
2 answers:
Scilla [17]3 years ago
5 0
The answer is the second one of it that
tatuchka [14]3 years ago
3 0

Answer:

a) The blue and red chairs experienced the strongest force because they are both more massive than the yellow chair and they changed speed by the same amount.

Explanation:

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A proton and an alpha particle are momentarily at rest at adistance r from each other. They then begin to move apart.Find the sp
Arte-miy333 [17]

Answer:

The unknown quantities are:

E and F

The final velocity of the proton is:

√(8/3) k e^2/(m*r)

Explanation:

Hello!

We can solve this problem using conservation of energy and momentum.

Since both particles are at rest at the beginning, the initial energy and momentum are:

Ei = k (q1q2)/r

pi = 0

where k is the coulomb constant (= 8.987×10⁹ N·m²/C²)

and q1 = e and q2 = 2e

When the distance between the particles doubles, the energy and momentum are:

Ef = k (q1q2)/2r + (1/2)m1v1^2 + (1/2)m2v2^2

pf = m1v1 + m2v2

with m1 = m,   m2 = 4m,    v1=vf_p,    v2 = vf_alpha

The conservation momentum states that:

pi = pf      

Therefore:

m1v1 + m2v2 = 0

That is:

v2 = (1/4) v1

The conservation of energy states that:

Ei = Ef

Therefore:

k (q1q2)/r = k (q1q2)/2r + (1/2)m1v1^2 + (1/2)m2v2^2

Replacing

      m1 =  m, m2 = 4m, q1 = e, q2 = 2e

      and   v2 = (1/4)v1

We get:

(1/2)mv1^2 = k e^2/r + (1/2)4m(v1/4)^2 =  k e^2/r + (1/8)mv1^2

(3/8) mv1^2 = k e^2/r

v1^2 = (8/3) k e^2/(m*r)

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3 years ago
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