The gravitation force is quartered when two objects' masses are halved without changing their distance.
Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.
F=(KM1 M2)/r^2
K= Gravitation force constant
M1M2 = masses of the object
r = distance between objects
When M1 and M2 are halved, it becomes M1/2 and M2/2
F=(K M1/2 x M2/2)/r^2
F=(K (M1 x M2)/4)/r^2
F=(KM1 x M2)/(4r^2 )
Recall
F=(KM1 x M2)/r^2
Therefore
F=F/4
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Answer: D
Neither A nor B
Explanation:
In order to check the clearances for rod and main bearings, you need a set of micrometers and a dial-bore gauge
Measuring the inside diameter of a main or rod bearing will require a dial bore gauge. The best ones to use are accurate down to 0.0001-inch.
So, both technician A and B are incorrect
At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change.
Answer:
hope this helps you're welcome
<h2>Answer:</h2><h2>The depth of barge float=
3 cm</h2><h2>
Explanation:</h2>
Length of rectangular barge=5.2 m
Width of rectangular barge=2.4m
Mass of crate=410 kg
Let h be the height of barge float
Volume of barge float=
Density of water=
Weight of water displaced by barge=Buoyant force=-Weight of horse
1 m=100 cm
cm
Hence, the depth of barge float=3 cm
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