Answer: 10ft
Since
= 9.48 which is 10 when you round it to the nearest ft.
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Explanation
The shaded area represents a segment. This can be solved with the formula below;

Since the triangle is an equilateral triangle, it implies that the angle subtended at the centre is 60 degrees. Also, the given radius is 7 cm
![\begin{gathered} =7^2(\frac{60}{360}\times3.14-\frac{1}{2}\times\sin 60)^{}_{} \\ =49(\frac{3.14}{6}-\frac{\sqrt[]{3}}{4}) \\ =4.43\operatorname{cm}^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D7%5E2%28%5Cfrac%7B60%7D%7B360%7D%5Ctimes3.14-%5Cfrac%7B1%7D%7B2%7D%5Ctimes%5Csin%2060%29%5E%7B%7D_%7B%7D%20%5C%5C%20%3D49%28%5Cfrac%7B3.14%7D%7B6%7D-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B4%7D%29%20%5C%5C%20%3D4.43%5Coperatorname%7Bcm%7D%5E2%20%5Cend%7Bgathered%7D)
Answer:
Answer: 
<u>Step-by-step explanation:</u>
![\text{Use the distance formula: }d_AB=\sqrt{(x_A-x_B)^2+(y_A-y_B)^2}\\where\ (X_A, y_A)=(-3, -2)\\and\ (x_B,y_B)=(4, -7)\\\\\\d_AB=\sqrt{(-3-4)^2+[-2-(-7)]^2}\\\\.\quad =\sqrt{(-7)^2+(5)^2}\\\\.\quad =\sqrt{49+25}\\\\.\quad =\boxed{\sqrt{74}}](https://tex.z-dn.net/?f=%5Ctext%7BUse%20the%20distance%20formula%3A%20%7Dd_AB%3D%5Csqrt%7B%28x_A-x_B%29%5E2%2B%28y_A-y_B%29%5E2%7D%5C%5Cwhere%5C%20%28X_A%2C%20y_A%29%3D%28-3%2C%20-2%29%5C%5Cand%5C%20%28x_B%2Cy_B%29%3D%284%2C%20-7%29%5C%5C%5C%5C%5C%5Cd_AB%3D%5Csqrt%7B%28-3-4%29%5E2%2B%5B-2-%28-7%29%5D%5E2%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Csqrt%7B%28-7%29%5E2%2B%285%29%5E2%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Csqrt%7B49%2B25%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Cboxed%7B%5Csqrt%7B74%7D%7D)
Something to remember is how to multiply terms with same bases, but different exponents:

Essentially, we add the exponents.
Using the information above, we can find our answer:

Our answer is
, or A.