1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

Multiplying both sides by 100 we get:


Subtracting both sides by 36000 we get:


Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer:
90
Step-by-step explanation:
the colums add up to angle 1, which make angle 2 adjacent.
9-9=0
100/6 = 16.66 rounds to 16.7
Answer:
D. 15
Step-by-step explanation:
<em>Use proportions.</em>
<em />
<em />