Answer:
52, 50, 54, 54, 56
Explanation:
The "stem" in this scenario is the tens digit of the number. Each "leaf" is the ones digit of a distinct number with the given tens digit.
5 | 20446 represents the numbers 52, 50, 54, 54, 56
Answer:
hello im new trying to get points
Explanation:
Answer: b)Its ability to penetrate skin quickly due to its very small diameter
Explanation: Carbon nano tubes(CNT) are the material widely used in the medical field due to the atomic structure of it ans also have small size. Toxicity in the carbon nano tubes is because their small sized atomic particles which can enter the skin by penetration or inhalation. But are still preferred in the medicine because having unique properties like mechanical property, chemical property,surface property etc.
Answer with Explanation:
Assuming that the degree of consolidation is less than 60% the relation between time factor and the degree of consolidation is
![T_v=\frac{\pi }{4}(\frac{U}{100})^2](https://tex.z-dn.net/?f=T_v%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%28%5Cfrac%7BU%7D%7B100%7D%29%5E2)
Solving for 'U' we get
![\frac{\pi }{4}(\frac{U}{100})^2=0.2\\\\(\frac{U}{100})^2=\frac{4\times 0.2}{\pi }\\\\\therefore U=100\times \sqrt{\frac{4\times 0.2}{\pi }}=50.46%](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B4%7D%28%5Cfrac%7BU%7D%7B100%7D%29%5E2%3D0.2%5C%5C%5C%5C%28%5Cfrac%7BU%7D%7B100%7D%29%5E2%3D%5Cfrac%7B4%5Ctimes%200.2%7D%7B%5Cpi%20%7D%5C%5C%5C%5C%5Ctherefore%20U%3D100%5Ctimes%20%5Csqrt%7B%5Cfrac%7B4%5Ctimes%200.2%7D%7B%5Cpi%20%7D%7D%3D50.46%25)
Since our assumption is correct thus we conclude that degree of consolidation is 50.46%
The consolidation at different level's is obtained from the attached graph corresponding to Tv = 0.2
i)
= 71% consolidation
ii)
= 45% consolidation
iii)
= 30% consolidation
Part b)
The degree of consolidation is given by
![\frac{\Delta H}{H_f}=U\\\\\frac{\Delta H}{1.0}=0.5046\\\\\therefore \Delta H=50.46cm](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20H%7D%7BH_f%7D%3DU%5C%5C%5C%5C%5Cfrac%7B%5CDelta%20H%7D%7B1.0%7D%3D0.5046%5C%5C%5C%5C%5Ctherefore%20%5CDelta%20H%3D50.46cm)
Thus a settlement of 50.46 centimeters has occurred
For time factor 0.7, U is given by
![T_v=1.781-0.933log(100-U)\\\\0.7=1.781-0.933log(100-U)\\\\log(100-U)=\frac{1.780-.7}{0.933}=1.1586\\\\\therefore U=100-10^{1.1586}=85.59](https://tex.z-dn.net/?f=T_v%3D1.781-0.933log%28100-U%29%5C%5C%5C%5C0.7%3D1.781-0.933log%28100-U%29%5C%5C%5C%5Clog%28100-U%29%3D%5Cfrac%7B1.780-.7%7D%7B0.933%7D%3D1.1586%5C%5C%5C%5C%5Ctherefore%20U%3D100-10%5E%7B1.1586%7D%3D85.59)
thus consolidation of 85.59 % has occured if time factor is 0.7
The degree of consolidation is given by
![\frac{\Delta H}{H_f}=U\\\\\frac{\Delta H}{1.0}=0.8559\\\\\therefore \Delta H=85.59cm](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20H%7D%7BH_f%7D%3DU%5C%5C%5C%5C%5Cfrac%7B%5CDelta%20H%7D%7B1.0%7D%3D0.8559%5C%5C%5C%5C%5Ctherefore%20%5CDelta%20H%3D85.59cm)
Answer:
64.11% for 200 days.
t=67.74 days for R=95%.
t=97.2 days for R=90%.
Explanation:
Given that
β=2
Characteristics life(scale parameter α)=300 days
We know that Reliability function for Weibull distribution is given as follows
![R(t)=e^{-\left(\dfrac{t}{\alpha}\right)^\beta}](https://tex.z-dn.net/?f=R%28t%29%3De%5E%7B-%5Cleft%28%5Cdfrac%7Bt%7D%7B%5Calpha%7D%5Cright%29%5E%5Cbeta%7D)
Given that t= 200 days
![R(200)=e^{-\left(\dfrac{200}{300}\right)^2}](https://tex.z-dn.net/?f=R%28200%29%3De%5E%7B-%5Cleft%28%5Cdfrac%7B200%7D%7B300%7D%5Cright%29%5E2%7D)
R(200)=0.6411
So the reliability at 200 days 64.11%.
When R=95 %
![0.95=e^{-\left(\dfrac{t}{300}\right)^2}](https://tex.z-dn.net/?f=0.95%3De%5E%7B-%5Cleft%28%5Cdfrac%7Bt%7D%7B300%7D%5Cright%29%5E2%7D)
by solving above equation t=67.74 days
When R=90 %
![0.90=e^{-\left(\dfrac{t}{300}\right)^2}](https://tex.z-dn.net/?f=0.90%3De%5E%7B-%5Cleft%28%5Cdfrac%7Bt%7D%7B300%7D%5Cright%29%5E2%7D)
by solving above equation t=97.2 days