Answer:
Hello your question is incomplete attached below is the complete question
answer:
Considering Laminar flow
Q ( heat ) will be independent of diameter
Considering Turbulent flow
The heat transfer will increase with decreasing "dia" for the turbulent
heat transfer = f(d^-0.8 )
Explanation:
attached below is the detailed solution
Considering Laminar flow
Q ( heat ) will be independent of diameter
Considering Turbulent flow
The heat transfer will increase with decreasing "dia" for the turbulent
heat transfer = f(d^-0.8 )
Same question idea but different values... I hope I helped you... Don't forget to put a heart mark
The answer mostly likely is: “1” due to the fact it is well ordered, and follows a similar thought process, best of luck!
Answer:
The critical radius is -1.30 nm
Explanation:
Temperature for homogenous nucleation of copper, 
Melting point of copper, 
Latent heat of fusion, 
Surface free energy, 
Critical radius, r = ?
The formula for the critical radius is given by:



The critical radius is -1.30 nm