Answer:
The volume of the ring shaped solid that remains is 21 unit^3.
Explanation:
The total volume of the sphere is given as:
Volume of Sphere = (4/3)πr^3
where, r = radius of sphere
Volume of Sphere = (4/3)(π)(5)^3
Volume of Sphere = 523.6 unit^3
Now, we find the volume of sphere removed by the drill:
Volume removed = (Cross-sectional Area of drill)(Diameter of Sphere)
Volume removed = (πr²)(D)
where, r = radius of drill = 4
D = diameter of sphere = 2*5 = 10
Therefore,
Volume removed = (π)(4)²(10)
Volume removed = 502.6 unit^3
Therefore, the volume of ring shaped solid that remains will be the difference between the total volume of sphere, and the volume removed.
Volume of Ring = Volume of Sphere - Volume removed
Volume of Ring = 523.6 - 502.6
<u>Volume of Ring = 21 unit^3</u>
