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2 years ago

Marking brainliest hurry !

Chemistry

2 answers:

jek_recluse [69]2 years ago

7 0

Answer:

B. A body at rest will stay at rest until it is acted upon by another object

Explanation:

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Kitty [74]2 years ago

5 0

Answer:

The correct answer is b.

Explanation:

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A car is traveling 150 km in 7200 s what is the speed of the car

noname [10]

Speed = Distance divided by time
Speed = 150 km / 7200 s
Speed = 1 km / 48 s

3 0

3 years ago

Suppose the concentration of the standard stock solution is 50.04 ppm and that you delivered 4.60 mL of this standard stock solu

12345 [234]

Answer:

9.21 ppm

Explanation:

Considering

$concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}$

Given that:

$concentration_{working\ solution}=?$

$Volume_{working\ solution}=25.00mL$

$Volume_{stock\ solution}=4.60mL$

$concentration_{stock\ solution}=50.04 ppm$

So,

$concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL$

$concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm$

4 0

3 years ago

Pleasee help me I really need an answer help

Juliette [100K]

Answer:

This is hard for me also but I am trying to find out answer

Explanation:

Please mark me as brainlist.

6 0

3 years ago

Sound is energy moving in

galben [10]

Whats do you want to know?

7 0

3 years ago

What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o

lyudmila [28]

Answer:

$\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%$

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

$atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu$

Thus, the atom percent turns out:

$\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%$

Best regards.

4 0

3 years ago