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Ludmilka [50]
2 years ago
13

Cars A and B travel along the same straight track. Car A is located at position s1 at clock reading t1 and it maintains a consta

nt speed of v1. Car B is located at position s2 < s1 at clock reading t2, and it maintains a constant speed of v2 > v1. Find an expression for the clock reading at which car B will overtake car A. Find also an expression for the position at which car B overtakes car A. Evaluate your expressions for the values s1 = 0.75 meters, t1 = 0.00 seconds, v1 = 0.38 m s−1 , s2 = 0.0 meters, t2 = 0.08 seconds, and v2 = 0.78 m s−1 .
Physics
1 answer:
m_a_m_a [10]2 years ago
7 0

Answer:

a) t=\frac{S1-V1*t1 - S2 + V2*t2}{V2-V1}

b) X = S2 - V2*t2 + V2*\frac{S1-V1*t1 - S2 + V2*t2}{V2-V1}

c) t = 2.031s      X = 1.52m

Explanation:

Let X1 be position of car A as a function of time and X2 be the position of car B as a function of time:

X1 = Xo1 + V1*t     If we evaluate this expression at t=t1

S1 = Xo1 + V1*t1    Solving for Xo1 we get its initial position at t=0:

Xo1 = S1 - V1*t1    

Similarly for car B:

Xo2 = S2 - V2*t2

Now, to find the instant when car B overtakes car A:

X1 = X2   Replacing their functions in time:

(S1 - V1*t1) + V1*t  = (S2 - V2*t2) + V2*t   Solving for t:

t=\frac{S1-V1*t1 - S2 + V2*t2}{V2-V1}   This is the instant when B reaches A

If we replace this expression in either X1 or X2 expression, we get that position:  X1 = X2

X1 = X2 = X = S2 - V2*t2 + V2*\frac{S1-V1*t1 - S2 + V2*t2}{V2-V1}

If we evaluate these two expressions with the given values:

t = 2.031s  and   X = 1.52m

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Fudgin [204]

1.7 x 10^2 N

or 166 N

First you find the vertical component of the weight, which is 9.8*40, (g*m), which is 392 N. You then find the angle between that and the slope, which is 90-25, which is 65. You then multiply the vertical weight by cos(65), to find the component of that that is parallel to the slope. You get 165.666 N

3 0
3 years ago
A long ramp made of cast iron is sloped at a constant angle θ = 52.0∘ above the horizontal. Small blocks, each with mass 0.42 kg
dezoksy [38]

Answer:

For cast iron we have

h = 0.92 m

For copper

h = 1.05 m

For Lead

h = 1.23 m

For Zinc

h = 2.43 m

Explanation:

As we know that final speed of the block is calculated by work energy theorem

W_f + W_g = \frac{1}{2}mv^2

now we have

-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2

now we have

v^2 = 2gh - 2\mu_k g h cot\theta

v = \sqrt{2gh(1 - \mu_k cot\theta)}

For cast iron we have

4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}

h = 0.92 m

For copper

4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}

h = 1.05 m

For Lead

4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}

h = 1.23 m

For Zinc

4 = \sqrt{2(9.81)(h)(1 - 0.85cot52)}

h = 2.43 m

4 0
3 years ago
Which of the following statements best describe destructive forces? A. Forces that build up, create, landmasses. B. Forces that
MissTica
<span>An event that breaks objects into smaller objects or pieces is called destructive force 
</span><span>Tornadoes, Hurricanes, Earthquakes, Volcanoes, Tsunamis and more are some of examples
</span><span>Forces that wear down, destroy is right answer</span>
4 0
3 years ago
A certain lightning bolt moves 10.0 C of charge. How many charges have been moved if the fundamental unit of charge is 1.6 x 10-
Andrej [43]

To solve this problem, use the ratio given by the total number of electrons or protons that exist as a function of the total charge, and inversely proportional to the value of the fundamental charge. The number of fundamental unit  |q_e| that constitutes a charge of 40.0C can be calculated as

N = \frac{|Q|}{|q_e|}

Here,

q_e = Value of charge and it is the fundamental charge

Q = Total Charge

N = Total number of electron or protons

The number of fundamental units is calculated as follows

N = \frac{10.0C}{1.6*10^{-19}C}

N = 6.25*10^{19}

Therefore the number of fundamental charge units moved by lightning bolt is 6.25*10^{19}

8 0
3 years ago
The speed of sound in air is around 330 m/s. If a bat emits a single high-pitched ‘click’ of sound in a cave that is 25m wide, c
Bingel [31]

Answer:

0.15 s

Explanation:

From the question given above, the following data were obtained:

Speed of sound (v) = 330 m/s

Distance (x) = 25 m

Time (t) =?

The time taken for the echo of the sound to the bat can be obtained as follow:

v = 2x / t

330 = 2 × 25 / t

330 = 50 / t

Cross multiply

330 × t = 50

Divide both side by 330

t = 50 / 330

t = 0.15 s

Thus, it will take 0.15 s for the echo of the sound to the bat

4 0
2 years ago
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