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Vinvika [58]
3 years ago
11

A 9mm bullet has a mass of 0.007 kg. When fired

Physics
1 answer:
Sonbull [250]3 years ago
3 0

Answer:

The velocity of the bullet is 380 m/s

Explanation:

The given parameters are;

The mass of the 9 mm bullet fired = 0.007 kg

The measure of the momentum the bullet has = 2.66 kg·m/s

The equation for linear momentum is given as follows;

The linear momentum of an object = The mass of the object × The velocity of the object

∴ The velocity of the object = The linear momentum of an object/(The mass of the object)

The velocity of the bullet = The linear momentum of an bullet/(The mass of the bullet)

The velocity of the bullet = 2.66 kg·m/s/(0.007 kg) = 380 m/s

The velocity of the bullet = 380 m/s.

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kupik [55]

Answer: A)30V. First find the current of the circuit. I=V/R(total resistance). So I=60/120=0.5. Now to find voltage drop in R3 use ohms law as given. V(of 3)=(0.5)(60)=30V

7 0
3 years ago
I have no clue what to do please help.
Yakvenalex [24]

Answer:

Step one : read the directions

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Explanation:

3 0
2 years ago
the ratio of the energy per second radiated by the filament of a lamp at 250k to that radiated at 2000k, assuming the filament i
Naily [24]

Answer:

(a) \frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b) P =  0.816 Watt

Explanation:

(a)

The power radiated from a black body is given by Stefan Boltzman Law:

P = \sigma AT^4

where,

P = Energy Radiated per Second = ?

σ = stefan boltzman constant = 5.67 x 10⁻⁸ W/m².K⁴

T = Absolute Temperature

So the ratio of power at 250 K to the power at 2000 K is given as:

\frac{P_{250k}}{P_{2000k}}=\frac{\sigma A(250)^4}{\sigma A(2000)^4}\\\\\frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b)

Now, for 90% radiator blackbody at 2000 K:

P = (0.9)(5.67\ x\ 10^{-8}\ W/m^2.K^4)(1\ x\ 10^{-6}\ m^2)(2000\ K)^4

<u>P =  0.816 Watt</u>

7 0
3 years ago
Amanda spent 2/5 of her time after school doing homework and ¼ of her remaining time riding her bike. If she rode her bike for 4
Doss [256]

Answer:120 min

Explanation:

Given

Amanda  spent \frac{2}{5} of her time after school doing Home work

And \frac{1}{4} of her remaining  time riding her bike

It is given that she rode her bike for 45 minutes in a week

Let t be the time after school

therefore Amanda spend \frac{2t}{5} in home work and  \frac{3t}{5} time is left

From remaining \frac{3t}{5} time she spends \frac{1}{4} time riding her bike

therefore \frac{3t}{5}\times \frac{1}{4}=45

thus t=300 min

therefore time  spent on home work is \frac{2}{5}\times 300=120 min

6 0
3 years ago
What will most likely happen ifa light wave moves through a solid?
levacccp [35]
It will decrease speed
7 0
3 years ago
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