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2 years ago

A 9mm bullet has a mass of 0.007 kg. When fired

Physics

1 answer:

Sonbull [250]2 years ago

3 0

Answer:

The velocity of the bullet is 380 m/s

Explanation:

The given parameters are;

The mass of the 9 mm bullet fired = 0.007 kg

The measure of the momentum the bullet has = 2.66 kg·m/s

The equation for linear momentum is given as follows;

The linear momentum of an object = The mass of the object × The velocity of the object

∴ The velocity of the object = The linear momentum of an object/(The mass of the object)

The velocity of the bullet = The linear momentum of an bullet/(The mass of the bullet)

The velocity of the bullet = 2.66 kg·m/s/(0.007 kg) = 380 m/s

The velocity of the bullet = 380 m/s.

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Answer:

Please find the explanation below

Explanation:

A hypothesis in science is a testable explanation that is yet to be tested via experimentation. It is a predictive statement or suggested solution to an observation. A hypothesis aims at finding a possible explanation/answer to a question, which is subject to testing. One important aspect of formulating a hypothesis is that it tends to connect the independent variable with the dependent/measurable variable.

The statement "RED IS A BEAUTIFUL COLOR" cannot be considered a hypothesis because it does not aim to answer a question that can undergo experimental testing. This statement can not be measured via experimentation. The statement is not a possible answer to a question but rather a personal opinion about something.

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3 years ago

Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp

slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

$Q=Av$

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

$Q=1.20 m^3/s$

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r = 0.260 m

So the cross-sectional area is

$A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2$

So we can re-arrange the equation to find the speed of the water:

$v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s$

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

$Q_1 = Q_2\\A_1 v_1 = A_2 v_2$

where we have

$A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s$

and where $A_2$ is the cross-sectional area of the pipe at the second point.

Solving for A2,

$A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2$

And finally we can find the radius of the pipe at that point:

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2 years ago

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Answer:

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The use of genetic factors to influence the growth of a plant encompasses manipulating the genetic constituent (gene) of such plant.

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