Vertical:
(20 m/s) sin(25º) ≈ 8.45 m/s
Horizontal:
(20 m/s) cos(25º) ≈ 18.1 m/s
Answer:
Explanation:
let force exerted by engine be F.Net force =( F-400)N, applying newton law
F-400 = 1.5 x 10³x18 =27000 ,
F = 27400 N.
velocity after 12 s = 0 + 18 x 12 = 216 m/s
Average velocity = (0 + 216 )/2 = 108 m/s
Average power = force x average velocity = 27400 x 108 = 29.6 10⁵ W .⁶
b) At 12 s , velocity = 216 m/s
Instantaneous power = velocity x force = 216 x 27400 = 59.2 x 10⁶ W.
Half mass car because it's traveling faster
The slope of the line is
(change in ' y ' between the ends) / (change in ' x ' between the ends)
Slope = (630g - 0) / (70 cm^3 - 0)
Slope = (630 / 70) g/cm^3
<em>Slope = 9.0 g/cm^3</em>
Answer: Option B: 1.3×10⁵ W
Explanation:
Work Done, 
Where s is displacement in the direction of force and F is force.
where, v is the velocity.
It is given that, F = 5.75 × 10³N
v = 22 m/s
P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W
Thus, the correct option is B
