Answer:
![p_{H_2O}=2.00atm](https://tex.z-dn.net/?f=p_%7BH_2O%7D%3D2.00atm)
Explanation:
Hello!
In this case, according to the following chemical reaction:
![2H_2+O_2\rightarrow 2H_2O](https://tex.z-dn.net/?f=2H_2%2BO_2%5Crightarrow%202H_2O)
It means that we need to compute the moles of hydrogen and oxygen that are reacting, via the ideal gas equation as we know the volume, pressure and temperature:
![n_{H_2}=\frac{3.00atm*1.00L}{0.08206\frac{atm*L}{mol*K}*400K}=0.0914molH_2 \\\\n_{O_2}=\frac{1.00atm*1.00L}{0.08206\frac{atm*L}{mol*K}*400K}=0.0305molH_2](https://tex.z-dn.net/?f=n_%7BH_2%7D%3D%5Cfrac%7B3.00atm%2A1.00L%7D%7B0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A400K%7D%3D0.0914molH_2%20%5C%5C%5C%5Cn_%7BO_2%7D%3D%5Cfrac%7B1.00atm%2A1.00L%7D%7B0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A400K%7D%3D0.0305molH_2)
Thus, the yielded moles of water are computed by firstly identifying the limiting reactant:
![n_{H_2O}^{by\ H_2} = 0.0914molH_2*\frac{2molH_2O}{2molH_2} =0.0914molH_2O\\\\n_{H_2O}^{by\ O_2} = 0.0305molO_2*\frac{2molH_2O}{1molO_2} =0.0609molH_2O](https://tex.z-dn.net/?f=n_%7BH_2O%7D%5E%7Bby%5C%20H_2%7D%20%3D%200.0914molH_2%2A%5Cfrac%7B2molH_2O%7D%7B2molH_2%7D%20%3D0.0914molH_2O%5C%5C%5C%5Cn_%7BH_2O%7D%5E%7Bby%5C%20O_2%7D%20%3D%200.0305molO_2%2A%5Cfrac%7B2molH_2O%7D%7B1molO_2%7D%20%3D0.0609molH_2O)
Thus, the fewest moles of water are 0.0609 mol so the limiting reactant is oxygen; in such a way, by using the ideal gas equation once again, we compute the pressure of water:
![p_{H_2O}=\frac{0.0609molH_2O*0.08206\frac{atm*L}{mol*K}*400K}{1.00L}\\\\ p_{H_2O}=2.00atm](https://tex.z-dn.net/?f=p_%7BH_2O%7D%3D%5Cfrac%7B0.0609molH_2O%2A0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A400K%7D%7B1.00L%7D%5C%5C%5C%5C%20p_%7BH_2O%7D%3D2.00atm)
Best regards!
Answer:
liquid will be evaporated while solid remains
Answer:
The mass of
4.6
×
10
24
atoms of silver is approximately 820 g.
Explanation:
In order to determine the mass of a given number of atoms of an element, identify the equalities between moles of the element and atoms of the element, and between moles of the element and its molar mass.
1
mole atoms Ag=6.022xx10
23
atoms Ag
Molar mass of Ag =#"107.87 g/mol"#
Multiply the given atoms of silver by
1
mol Ag
6.022
×
23
atoms Ag
. Then multiply times the molar mass of silver.
4.6
×
10
24
atoms Ag
×
1
mol Ag
6.022
×
10
23
atoms Ag
×
107.87
g Ag
1
mol Ag
=
820 g Ag