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Ivenika [448]
3 years ago
9

What is "In an isolated system two cars, each with a mass of 2,000 kg, collide. Car 1 is initially at rest , while car 2 was mov

ing at 20 m/s. what is their combined momentum after the collision?"
Physics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

Final velocity of the combining cars = 10m/s

combined momentum = 40000kgm/s

Explanation:

Given the following :

Mass of both colliding cars = 2000kg

Initial Velocity of car 1 (U1) = 0

Initial Velocity of car 2 (U2) = 20m/s

Combuned momentum after collision =?

This is an inelastic collision which is calculated thus :

M1U1 + M2U2 = M1V + M2V

M1U1 + M2U2 = (M1 + M2) V

Where V = "final Velocity of the colliding bodies

2000 × 0 + 2000 × 20 = (2000 + 2000) V

0 + 40000 = 4000V

V = 40000 / 4000

V = 10m/s

Therefore combined momentum = (M1 + M2) V

(2000 + 2000) 10

4000(10) = 40000kgm/s

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Answer:

The magnetic force points in the positive z-direction, which corresponds to the upward direction.

Option 2 is correct, the force points in the upwards direction.

Explanation:

The magnetic force on any charge is given as the cross product of qv and B

F = qv × B

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v = velocity of the charged ball = (+vî) (velocity is in the eastern direction)

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F = qv × B = (+qvî) × (Bj)

F =

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F = i(0 - 0) - j(0 - 0) + k(qvB - 0)

F = (qvB)k N

The force is in the z-direction.

We could also use the right hand rule; if we point the index finger east (direction of the velocity), the middle finger northwards (direction of the magnetic field), the thumb points in the upward direction (direction of the magnetic force). Hence, the magnetic force is acting upwards, in the positive z-direction too.

Hope this Helps!!!

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Which of the following distinguishes the isotope uranium-238 from the isotope uranium-235?
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Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point. F⃗ 1F→1F_1_vec has a magnitude of 9.20 NN and is directed at an a
marishachu [46]

Answer:

-9.46 N

Explanation:

In order to get the value of the x component of the resultant force, we need to get the value of the x component of each force.

This value will be the projection of the force vector, on the x-axis.

For F₁, as it is directed at an angle of 55.0º above the negative x axis, we can find F₁ₓ just applying the definition of cosine of an angle, as follows:

cos θ = \frac{x}{r}

In this case, x = F₁ₓ, and r = F₁

θ, measured from the positive x axis counterclockwise, is as follows:

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We can repeat the process for F₂, as follows:

For F₂, as it is directed at an angle of 53.3º below the negative x axis, we can find F₂ₓ just applying the definition of cosine of an angle, as follows:

cos θ = \frac{x}{r}

In this case, x = F₂ₓ, and r = F₂

θ, measured from the positive x axis counterclockwise, is as follows:

θ= 180º + 53.3º = 233.3º

⇒ F₂ₓ = F₂* cosθ = 7.00 N * cos 233.3º = -4.18 N

The total component of both forces along the x axis, can be found just adding both components, as follows:

Fₓ = F₁ₓ + F₂ₓ = -5.28 N + -4.18 N = -9.46 N

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3 years ago
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