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Ivenika [448]
3 years ago
9

What is "In an isolated system two cars, each with a mass of 2,000 kg, collide. Car 1 is initially at rest , while car 2 was mov

ing at 20 m/s. what is their combined momentum after the collision?"
Physics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

Final velocity of the combining cars = 10m/s

combined momentum = 40000kgm/s

Explanation:

Given the following :

Mass of both colliding cars = 2000kg

Initial Velocity of car 1 (U1) = 0

Initial Velocity of car 2 (U2) = 20m/s

Combuned momentum after collision =?

This is an inelastic collision which is calculated thus :

M1U1 + M2U2 = M1V + M2V

M1U1 + M2U2 = (M1 + M2) V

Where V = "final Velocity of the colliding bodies

2000 × 0 + 2000 × 20 = (2000 + 2000) V

0 + 40000 = 4000V

V = 40000 / 4000

V = 10m/s

Therefore combined momentum = (M1 + M2) V

(2000 + 2000) 10

4000(10) = 40000kgm/s

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LSE
Zinaida [17]
B) initial speed (u)=3
final speed (v)=8
time (t)= 10
acceleration (a)=?

v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²

c)displacement (s)=?
1st section of journey

v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters

2nd section of journey
a=0
t=7
u=8
s=?

s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters

56+55= 111 meters

(For graph x axis =time (sec) & y axis= velocity (m/s))

6 0
3 years ago
Which statement is true about the gravitational force?
topjm [15]

Hello,

I think that A is the right one.

6 0
4 years ago
Read 2 more answers
Draw a closed circuit diagram of the battery of 2 cells arranged in series, connecting wire, switch and bulb; mark the direction
ch4aika [34]
This is the open switch 2 cells connecting wire and bulb

5 0
3 years ago
Conversations with astronauts on lunar walks had an echo that was used to estimate the distance to the Moon. The sound spoken by
dmitriy555 [2]

Answer:

d ≈ 320000 km

Explanation:

Echoes occurs as a result of the bouncing back of sound waves as it impinges on an obstacle. Since the echo covers two distances (i.e forth and back) the distance is written as 2d.

Velocity of radio waves is taken as the speed of light = 3*10^{8}m/s^{2}

time =2.15s

DISTANCE = VELOCITY *TIME

2d=vt

d=\frac{vt}{2}

d=\frac{3*10^{8}*2.15}{2}

    d= 322500000m

Distance to the moon is approximately 320000km

4 0
3 years ago
A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy
tensa zangetsu [6.8K]

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

3 0
3 years ago
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