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2 years ago

14

I WILL MARK YOU THE BRAINLIEST NO LINKS

1 answer:

aliya0001 [1]2 years ago

6 0

Answer:

it is 30 newtons to the left

Explanation:

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Be-36 what hull type is best for use on ponds, small lakes and calm rivers?

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The hull type that is best for use on ponds, small lakes and calm rivers is Flat Bottom Hull.
A flat bottomed boat is a boat with a flat bottomed, two-chined hull, which allows it to be used in shallow bodies of water, such as rivers, because it is less likely to ground. The flat hull also makes the boat more stable in calm water.

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2 years ago

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A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.

juin [17]

Answer:

Explanation:

Given

For first case

launch angle $\theta =45^{\circ}C$

at highest point $h=150 m/s$

$150=u\cos 45$

$u=\frac{150}{\cos 45}=212.132 m/s$

For second case

$\theta _2=37^{\circ}C$

at highest Point velocity is $u\cos \theta _2$

$=212.132\times \cos 37$

$=169.41 m/s$

as there is no acceleration in x direction therefore horizontal velocity is same

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2 years ago

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Find the Input force, if the Mechanical Advantage of the simple machine used is 5 and Output force is 50 N.

galina1969 [7]

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6N

Explanation:

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2 years ago

Describe grafting, what are the<br> three methods?

Tanya [424]

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I hope I helped , Have a great day or night . Xoxoxo.

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2 years ago

An automobile traveling 89.0 km/h has tires of 62.0 cm diameter. (a) What is the angular speed of the tires about their axles? (

bekas [8.4K]

Answer:

a) 79.7rad/s

b) -18.7rad/s^2

c) 53m

Explanation:

We will use the MKS system of unit, so:

$v=89.0km/h=89.0\frac{km}{h}*\frac{1000m.h}{3600km.s}=24.7m/s\\\\d=62.0cm=62.0cm*\frac{0.01m}{1cm}=0.62m$

now, The angular speed is given by:

$\omega=\dfrac{v}{\frac{d}{2}}\\\\\\\omega=\frac{24.7m/s}{0.31m}=79.7rad/s$

in order to obtain the angular acceleration we have to apply the following formula:

$(\omega_f)^2=(\omega_o)^2+2\alpha*\theta\\\\\alpha=-\frac{(\omega_o)^2}{2*rev*2\pi}\\\\\alpha=-\frac{(79.7m/s)^2}{2*27*2\pi}=-18.7rad/s^2$

The linear displacement is given by:

$d_l=\theta*r\\d_l=rev*2\pi*\frac{d}{2}\\\\d_l=27*2\pi*0.31m=53m$

3 0

2 years ago