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3 years ago

A fish lays eggs on a rock. Later a male fishes comes and fertilizes the eggs.

Physics

2 answers:

Lelu [443]3 years ago

8 0

sexual reproduction because yeah

Schach [20]3 years ago

6 0

Answer:

it's a

Explanation:

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Hii! help asap. i’ll give brainliest thanks!

telo118 [61]

Its acceleration will change

7 0

3 years ago

A 100 kg father and his 50 kg daughter stand on ice skates on a frozen pond. The daughter pushes on her father with a force of 5

Lana71 [14]

Answer:

Both feel same magnitude force.

Explanation:

Given that

Mass of father = 100 kg

Mass of daughter = 50 kg

From the third law of Newtons :

Every action have it reaction in opposite direction.It means that if any object apply a force on the other object then first object also feel force of same magnitude but in opposite direction.

It means that both father and her daughter will feel same magnitude of same but in opposite direction.

7 0

3 years ago

Read 2 more answers

A strong lightning bolt transfers an electric charge of about 31 C to Earth (or vice versa). How many electrons are transferred?

olchik [2.2K]

Answer:

$m=5.78\times 10^{-3}\ g$

$n_e=1.935\times 10^{20}$ is the no. of electrons

Explanation:

Given:

quantity of charge transferred, $Q=31\ C$

No. of electrons in the given amount of charge:

As we have charge on one electron $1.602\times 10^{-19}\ C$

so,

$n_e=\frac{Q}{e}$

$n_e=\frac{31}{1.602\times 10^{-19}}$

$n_e=1.935\times 10^{20}$ is the no. of electrons

Now if each water molecules donates one electron:

Then we require $n=1.935\times 10^{20}$ molecules.

Now the no. of moles in this many molecules:

$n_m=\frac{n}{N_A}$

where

$N_A=6.022\times 10^{23}$ Avogadro No.

$n_m=\frac{1.935\times 10^{20}}{6.022\times 10^{23}}$

$n_m=3.213\times 10^{-4}\ moles$

We have molecular mass of water as M=18 g/mol.

So, the mass of water in the obtained moles:

$n_m=\frac{m}{M}$

where:

m = mass in gram

$3.213\times 10^{-4}=\frac{m}{18}$

$m=5.78\times 10^{-3}\ g$

7 0

3 years ago

A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne

Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

$W_x = 500 cos37$