Answer:
It has moved a distance, S = 25.9 m
Explanation:
F = 40 v²........(1)
.........(2)
Equating (1) and (2)
Integrate both sides:
.
What is the purpose of the lenses in a camera? a. Send light to the eyepiece c. Make the picture color or black and white b. Foc
2 answers:
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(a) Away from the normal
We can find the direction of bending of the ray of light by using Snell's equation:
where we have:
n1, n2: index of refraction of the first and second medium
; angle that the incident and the refracted ray form with the normal to the surface
Here, the light ray moves from a material with high index of refraction to a material with lower index, so we have
Re-arranging Snell's law we find
since we have
this implies
so the ray of light bends away from the normal.
(b) The wavelength is greater in the second material (the one with lower index of refraction)
The wavelength of the light in a medium is given by
where
is the wavelength of the light in a vacuum
n is the refractive index
The equation can be rewritten as
and again it can be rewritten as
where
Therefore, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.
(c) The frequency remains the same
Wavelength and speed of a light ray depend on the medium in which the wave is travelling through, however the frequency does not depend on that, so it remains the same in the two mediums.
Answer:
4.0 m/s
Explanation:
The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.
Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is
where here we have
d = 3.0 m is the horizontal distance covered
vx is the horizontal velocity
t = 1.3 s is the duration of the fall
Solving for vx,
Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by
where
h = 4.0 m is the initial height
vy is the initial vertical velocity
We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy
So now we can find the magnitude of the initial velocity: