Answer:
option c is correct
47.2%
Explanation:
given data
consisting of refrigerant = 134 a
volume V = 0.01 m³/kg
pressure P = 1MPa = 1000 kPa
to find out
quality of the R 134a
solution
we will get here value of volume Vf and Vv from pressure table 60 kpa to 3 Mpa for 1 Mpa of R134 a
that is
Vf = 0.0008701 m³/kg
Vv = 0.0203 m³/kg
so we will apply here formula that is
quality = (V - Vf) / (Vv - Vf) ............1
put here value
quality = (0.01 - 0.0008701 ) / ( 0.0203 - 0.0008701 )
quality = 0.4698
so quality is 47 %
SO OPTION C IS CORRECT
Answer:
You can create high drag which allows a steeper angle without increasing your air speed on landing. you can reduce the length of landing role. Flaps are also used to increase the drag they are retracted when they are not needed. it is adviseable to down he flaps during the time of take off.
I just deleted among us :/
Answer:
16 seconds
Explanation:
Given:
C = 60
L = 4 seconds each = 4*4 =16
In this problem, the first 3 timing stages are given as:
200, 187, and 210 veh/h.
We are to find the estimated effective green time of the fourth timing stage. The formula for the estimated effective green time is:
Let's first find the fourth stage critical lane group ratio , using the formula:
Solving for , we have:
Let's also calculate the volume capacity ratio X,
X = 0.704
For the the estimated effective green time of the fourth timing stage, we have:
Substituting figures in the equation, we now have:
15.78 ≈ 16 seconds
The estimated effective green time of the fourth timing stage is 16 seconds