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Anastaziya [24]
3 years ago
7

What volume is needed to store 0.80 moles of helium gas at 204.6 kpa and 300 k?

Chemistry
1 answer:
shepuryov [24]3 years ago
3 0
Answer is: 9,7 L is needed to store helium gas.
n(He) = 0,80 mol.
p(He) = 204,6 kPa.
T = 300 K.
R = 8,314 J/K·mol; universal gas constant.
Use ideal law eqaution: p·V = n·R·T.
V = n·R·T / p.
V(He) = 0,80 mol · 8,314 J/K·mol · 300 K ÷ 204,6 kPa.
V(He) = 9,75 L.


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Compute for the amount of H in the compound. The data you need to know are the following:
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Divide the least number between the two to each of their individual amounts:
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