Answer:
289282
Explanation:
r = Radius of plate = 0.52 mm
d = Plate separation = 0.013 mm
A = Area = 
V = Potential applied = 2 mV
k = Dielectric constant = 40
= Electric constant = 
Capacitance is given by
Charge is given by
Number of electron is given by
The number of charge carriers that will accumulate on this capacitor is approximately 289282.
Answer:
115 kPa
Explanation:
Use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Assuming no elevation change, h₁ = h₂.
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
Plugging in values:
(582,000 Pa) + ½ (1000 kg/m³) (1.28 m/s)² = P + ½ (1000 kg/m³) (30.6 m/s)²
P = 115,000 Pa
P = 115 kPa
The frequency of the wheel is given by:
where N is the number of revolutions and t is the time taken. By using N=100 and t=10 s, we find the frequency of the wheel:
And now we can find the angular speed of the wheel, which is related to the frequency by:
Answer:
500J
Explanation:
The arrow will have an energy of 500J after it has been released from its state of rest.
This is compliance with the law of conservation of energy which states that "in every system, energy is neither created nor destroyed but transformed from one form to another".
- The energy at rest which is the potential energy is 500J
- This energy will be converted to kinetic energy in total after the arrow has been released.
- This way, no energy is lost and we can account for the energy transformations occurring.
