Identify two factors that increase the electric force between objects
1 answer:
You might be interested in
Answer:
So the 97 percentile for this case should be 1.88 degrees.
Explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Let X the random variable that represent the temperatures of a population, and for this case we know the distribution for X is given by:
Where and
.
And we want the top 97 percentile for the distribution, so we need a value a such that:
or
We need on the right tail of the distribution a value a that gives to us 97% of the area below and 3% of the area above. Both conditions are equivalent.
Let's use the condition , the best way to solve this problem is using the z score with the following formula:
So we need a value from the normal standard distribution that accumulates 0.97 of the area on the left and 0.03 on the right. This value on this case is 1.88 and we can founded with the following code in excel:
"=NORM.INV(0.97,0,1)"
The figure attached gives an approximation of the value and we can see that is near 1.88.
If we apply the z score formula to our case we have this:
So then based on the equalities we have this:
And if we solve for a we got:
So the 97 percentile for this case should be 1.88 degrees.
The second figure attached illustrate the solution for this case.
Answer:
a) I = 2279.5 N s , b) F = 3.80 10⁵ N, c) I = 3125.5 N s and d) F = 5.21 10⁵ N
Explanation:
The impulse is equal to the variation in the amount of movement.
I =∫ F dt = Δp
I = m - m v₀
Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero
² = V₀² - 2g y
² = 0 - 2 9.8 30.0
= √588
= 24.25 m/s
a) We calculate the impulse
I = 94 24.25 - 0
I = 2279.5 N s
b) Let's join the other expression of the impulse to calculate the average force
I = F t
F = I / t
F = 2279.5 / 6 10⁻³
F = 3.80 10⁵ N
just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n
c) I = m - m v₀
I = 94 8 - 94 (-24.25)
I = 3125.5 N s
d) F = I / t
F = 3125.5 / 6 10⁻³
F = 5.21 10⁵ N