D determined by its temperature
Answer:
The ping pong ball, the light molecules have greater speed
Explanation:
The kinetic energy of an object is defined as
![K=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
where
m is the mass of the object
v is its speed
It follows that the speed can be written as
![v=\sqrt{\frac{2K}{m}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2K%7D%7Bm%7D%7D)
In this problem, both the golf ball and the ping pong ball have kinetic energy K. However, the mass of a gold ball is larger (approx. 45 g) than that of a ping pong ball (approx. 4 g): therefore, since v is inversely proportional to the square root of the mass, it follows that the ping pong ball must have a greater speed in order to achieve the same kinetic energy of the golf ball.
The same argument can be applied to the gaseous mixture: if there are more massive molecules and light molecules, and if they all have the same kinetic energy, then this means that the light molecules must have a greater speed, as a result again of the equation
![v=\sqrt{\frac{2K}{m}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2K%7D%7Bm%7D%7D)
M g = 5.00 (9.81) = 49.05
sin 21 = x149.05
x = 17.6N
Answer:
1.5min
Explanation:
To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.
By definition centripetal acceleration is given by
![a_c = \frac{V^2}{r}](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7BV%5E2%7D%7Br%7D)
Where,
V = Tangencial velocity
r = radius
With our values we know that
![a_c = \frac{V^2}{r}](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7BV%5E2%7D%7Br%7D)
![\frac{V^2}{r} = \frac{1}{10}g](https://tex.z-dn.net/?f=%5Cfrac%7BV%5E2%7D%7Br%7D%20%3D%20%5Cfrac%7B1%7D%7B10%7Dg)
Therefore solving to find V, we have:
![V = \sqrt{\frac{1}{10}g*r}](https://tex.z-dn.net/?f=V%20%3D%20%5Csqrt%7B%5Cfrac%7B1%7D%7B10%7Dg%2Ar%7D)
![V = \sqrt{\frac{9.81*200}{10}}](https://tex.z-dn.net/?f=V%20%3D%20%5Csqrt%7B%5Cfrac%7B9.81%2A200%7D%7B10%7D%7D)
![V = 14m/s](https://tex.z-dn.net/?f=V%20%3D%2014m%2Fs)
For definition we know that the Time to complete are revolution is given by
![t = \frac{Perimeter}{Speed}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7BPerimeter%7D%7BSpeed%7D)
![t = \frac{2\pi R}{V}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B2%5Cpi%20R%7D%7BV%7D)
![t = \frac{2\pi * 200}{14}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B2%5Cpi%20%2A%20200%7D%7B14%7D)
![t = 1.5min](https://tex.z-dn.net/?f=t%20%3D%201.5min)
Explanation:
Resistance is defined as the ability of a substance to resist the flow of current through the substance. Formula to calculate resistance is as follows.
R =
As outer surface of a wire is in the shape of sphere. therefore, its area will be as follows.
A = ![4 \pi r^{2}](https://tex.z-dn.net/?f=4%20%5Cpi%20r%5E%7B2%7D)
or, A = ![4 \pi (\frac{d}{2})^{2}](https://tex.z-dn.net/?f=4%20%5Cpi%20%28%5Cfrac%7Bd%7D%7B2%7D%29%5E%7B2%7D)
where, d = diameter of the sphere
This means that with increase in diameter of a conductor there will occur an increase in area of the wire. As area is inversely proportional to resistance so, increase in area will lead to a decrease in resistance.
On the other hand, relation between resistivity and temperature is as follows.
![\rho \propto \frac{1}{d} \propto A^{2} \propto T](https://tex.z-dn.net/?f=%5Crho%20%5Cpropto%20%5Cfrac%7B1%7D%7Bd%7D%20%5Cpropto%20A%5E%7B2%7D%20%5Cpropto%20T)
where,
= resistivity
d = mean free path of electrons
A = amplitude of atomic vibrations
T = temperature
Also, resistivity is directly proportional to resistance. So, with increase in temperature there will occur an increase in resistance of the conductor.
Thus, we can conclude that only technician B is correct.