Answer:
The energy should be high.
Explanation:
Bonds do store energy and release it depending if it's endothermic or exothermic. The energy should be low because when a bond forms (endothermic) it releases heat, which helps form bonds. Having a high energy means the bond is absorbing energy, which helps break bonds (endothermic). How this helps!
It’s b. Shared between two atoms.
In a chemical reaction, matter can neither be created nor destroyed, so the products that come out of a reaction must equal the reactants that go into a reaction. Stoichiometry is the measure of the elements within a reaction.[1] It involves calculations that take into account the masses of reactants and products in a given chemical reaction. Stoichiometry is one half math, one half chemistry, and revolves around the one simple principle above - the principle that matter is never lost or gained during a reaction. The first step in solving any chemistry problem is to balance the equation.
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The mass of steam required to raise the temperature of water is 3.5 g.
The given parameters;
- <em>mass of the benzene, = 47.6</em>
- <em>initial temperature of the benzene, = 5.5 ⁰C</em>
- <em>final temperature of the benzene = 30 ⁰C</em>
The molar mass of Benzene = 78.11 g/mol
The molar mass of water = 18 g/mol
The number of moles of the Benzene is calculated as follows;

The mass of steam required is calculated as follows;
<em>heat lost by steam = heat absorbed by benzene</em>
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Thus, the mass of steam required to raise the temperature of water is 3.5 g.
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339 grams of CLF3 is formed when F2 is in excess and 130 grams of CL2 reacts.
Explanation:
The balanced chemical reaction for the formation of ClF3 is given by:
+ 3
⇒ 2 Cl
the mass of Cl2 is given 130 grams
From the equation it is found that 2 moles of chloride reacts to form 2 moles of ClF3.
calculating the number of moles of chlorine by the formula:
Number of moles = mass of the substance ÷ atomic mass of one mole of the substance
n = 130 ÷ 35.45
= 3.6671 moles
So, applying stoichiometry
2 moles of Cl2 formed 2 moles of ClF3
3.6671 moles of Cl2 will form x moles of ClF3
2 ÷ 2 = x ÷ 3.6671
x = 3.6671 moles of ClF3
now from the formula of number of moles
weight is calculated as n × mass of the gas
3.6671 × 92.448
= 339.01 grams of ClF3 is formed.