Repeated experimental observations that describe aspects of the universe
The moles of O2 that are needed to react completely with 35.0 mol C2H2 is 87.5 moles of O2
<u><em>Explanation</em></u>
Write a balanced chemical equation for reaction of between C2H2 and O2
2 C2H2 + 5O2 → 4 CO2 + 2 H2O
if 35.0 moles C2H2 reacted then use the o mole ratio to determine the moles of C2H2
The mole ratio of C2H2 :O2 = 2:5 therefore the moles of O2
= 35 moles x5/2 = 87.5 moles of O2
Answer:
D.When the boiling points of the components are different
Explanation:
I believe the formal name for this procedure is actually distillation.
Answer:
Mass of Ag produced = 64.6 g
Note: the question is, how many grams of Ag is produced from 19.0 g of Cu and 125 g of AgNO3
Explanation:
Equation of the reaction:
Cu + 2AgNO3 ---> 2Ag + Cu(NO3)2
From the equation above, 1 mole of Cu reacts with 2 moles of AgNO3 to produce 2 moles of Ag and 1 mole of Cu(NO3)2.
Molar mass of the reactants and products are; Cu = 63.5 g/mol, Ag = 108 g/mol, AgNO3 = 170 g/mol, Cu(NO3)2 = 187.5 g/mol
To determine, the limiting reactant;
63.5 g of Cu reacts with 170 * 2 g of AgNO3,
19 g of Cu will react with (340 * 19)/63.5 g of AgNO3 =101.7 g of AgNO3.
Since there are 125 g of AgNO3 available for reaction, it is in excess and Cu is the limiting reactant.
63.5 g of Cu reacts to produce 108 * 2 g of Ag,
19 g of Cu will react to produce (216 * 19)/63.5 g of Ag = 64.6 g of Ag.
Therefore mass of Ag produced = 64.6g