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2 years ago

10

What kind of mixture is the copper chloride and water ? Explain why please !!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!

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1 answer:

Eva8 [605]2 years ago

8 0

Answer:

Explanation:

The word computer dates to the 1600s, so if you want to know the trems etymology, you will have to start your research in the time period.

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Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur

Vesna [10]

Answer:

a) Step 1:

$2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)$

Step 2:

$2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)$

b) The overall balanced reaction for given process is ;

$3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)$

Explanation:

a)

Galena = $PbS$

Lead(II) oxide = $PbO$

Sulfur dioxide = $SO_2$

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

$2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)$ ..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

$2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)$ ..[2]

b)

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

$3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)$

5 0

3 years ago

Read 2 more answers

How many molecules are in 10.00 moles of h2o?

weeeeeb [17]

The answer is 6.02e24 molecules or 6.02x10^24 molecules.

3 0

3 years ago

Write the full electron configuration for the element that is n=4 and has 5 valence electrons.

alukav5142 [94]

Answer:

Greg rusedski is not a fan on his side but answer to village in the future will have to go to a job 6y6666666 and the other two 5 to be 56th 6out and 6 to 56 to 5

4 0

2 years ago

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro

Zolol [24]

This is an incomplete question, here is a complete question.

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is approximately $2.15\times 10^6m/s$ ?

Find the force acting on the electron as it revolves in a circular orbit of radius $5.34\times 10^{-11}m$ .

Answer : The force acting on electron is, $7.9\times 10^{-8}N$

Explanation :

Formula used :

$F=\frac{mv^2}{r}$

where,

F = force acting on electrons

m = mass of electrons = $9.1\times 10^{-31}kg$

v = speed of electron = $2.15\times 10^6m/s$

r = radius of circular orbit = $5.34\times 10^{-11}m$

Now put all the given values in the above formula, we get:

$F=\frac{(9.1\times 10^{-31}kg)\times (2.15\times 10^6m/s)^2}{5.34\times 10^{-11}m}$

$F=7.9\times 10^{-8}N$

Thus, the force acting on electron is, $7.9\times 10^{-8}N$

8 0

2 years ago

Consider the following data. NO2(g) equilibrium reaction arrow identifying the requirement for light NO(g) + O(g) K = 6.8 ✕ 10-4

LenKa [72]

Answer:

$K=3.9*10^{-82}$

Explanation:

Reactions:

$NO_2 (g) \longleftrightarrow NO (g) +O (g)$

With: $K_1=\frac{[NO][O]}{[NO_2]}=6.8*10^{-49}$

$O_3 (g) + NO (g) \longleftrightarrow NO_2 (g) + O_2 (g)$

With: $K_2=\frac{[NO_2}{[O_3][NO]}=5.8*10^{-34}$

To achive the reaction we combine those two reactions:

$NO_2 (g) + O_3 (g) + NO (g) \longleftrightarrow NO (g) + O (g) + NO_2 (g)$

$O_3 (g) \longleftrightarrow O (g) + O_2 (g)$

The equilibrium constant:

$K= K_1*K_2=(6.8*10^{-49})*(5.8*10^{-34})=3.9*10^{-82}$

3 0

3 years ago