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3 years ago

What's the difference between work and power

2 answers:

8 0

Work is defined as the process of energy transfer to the motion of an object through the application of force. ... Power is defined as the amount of energy transferred in unit time. The SI unit of power is the watt.

You need to have power or energy, to be able to work. When you reach another lesson, you will learn about time, which is the flow of work you have done. You need more work than time for your work to count.

If you need more help, don't hesitate to ask!

May I please have brainliest?

Marizza181 [45]3 years ago

8 0

WORK is the amount of energy used to get something done.

POWER is the RATE at which the energy is used and the work is done.

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In your own words describe the motion of convection currents?

Marysya12 [62]

Convection is the circular motion that occurs as hotter air or liquid increases when the cooler air or liquid drops down, and has faster moving molecules, rendering it less dense. Convection currents within the earth shift layers of magma, and currents are formed by convection in the ocean.

5 0

3 years ago

Read 2 more answers

Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to

stiks02 [169]

Now, there is some information missing to this problem, since generally you will be given a figure to analyze like the one on the attached picture. The whole problem should look something like this:

"Beam AB has a negligible mass and thickness, and supports the 200kg uniform block. It is pinned at A and rests on the top of a post, having a mass of 20 kg and negligible thickness. Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to 360 N , the post slips at both B and C simultaneously."

Answer:

$\mu_{sB}=0.126$

$\mu_{sC}=0.168$

Explanation:

In order to solve this problem we will need to draw a free body diagram of each of the components of the system (see attached pictures) and analyze each of them. Let's take the free body diagram of the beam, so when analyzing it we get:

Sum of torques:

$\sum \tau_{A}=0$

$N(3m)-W(1.5m)=0$

When solving for N we get:

$N=\frac{W(1.5m)}{3m}$

$N=\frac{(1962N)(1.5m)}{3m}$

$N=981N$

Now we can analyze the column. In this case we need to take into account that there will be no P-ycomponent affecting the beam since it's a slider and we'll assume there is no friction between the slider and the column. So when analyzing the column we get the following:

First, the forces in y.

$\sum F_{y}=0$

$-F_{By}+N_{c}=0$

$F_{By}=N_{c}$

Next, the forces in x.

$\sum F_{x}=0$

$-f_{sB}-f_{sC}+P_{x}=0$

We can find the x-component of force P like this:

$P_{x}=360N(\frac{4}{5})=288N$

and finally the torques about C.

$\sum \tau_{C}=0$

$f_{sB}(1.75m)-P_{x}(0.75m)=0$

$f_{sB}=\frac{288N(0.75m)}{1.75m}$

$f_{sB}=123.43N$

With the static friction force in point B we can find the coefficient of static friction in B:

$\mu_{sB}=\frac{f_{sB}}{N}$

$\mu_{sB}=\frac{123.43N}{981N}$

$\mu_{sB}=0.126$

And now we can find the friction force in C.

$f_{sC}=P_{x}-f_{xB}$

$f_{sC}=288N-123.43N=164.57N$

$f_{sC}=N_{c}\mu_{sC}$

and now we can use this to find static friction coefficient in point C.

$\mu_{sC}=\frac{f_{sC}}{N}$

$\mu_{sC}=\frac{164.57N}{981N}$

$\mu_{sB}=0.168$

3 0

3 years ago

A person throws a rock 36 feet into the air straight up what was the rocks initial vertical speed

PilotLPTM [1.2K]

Answer:

Explanation:

Depends on how hard you throw it.

6 0

4 years ago

a voltmeter and an ammeter are used to respectively monitor the voltage across the current through the resistor

dusya [7]

When a current is established in a closed conducting loop , we use ammeter. Due to this resultant potential developed detected by voltmeter.

When current flows through loop , it gets conducted.
Due to this Electric field is generated . This happens due to induced magnetic field.
The free electrons were at rest until current is there , still ammeter detects some deflection.
This deflection is due to zero current.
Due to magnetic field , current in coil changes.
Mathematically, $\alpha =-\frac{d\beta }{dt}$
The presence of conducting loop is not necessary for having electric field.

$e= -\frac{d\beta }{dt}$

$e=-L\frac{d\beta }{dt}$

$i= i0 \left \{ {{y=0.63} \atop {x=t}} \right.$

i=0.63 io

To know more about voltmeter-

<u>brainly.com/question/1511135</u>

#SPJ4

8 0

1 year ago

Help please! Test tomorrow!

dlinn [17]

Earth distance to the Sun is about 40 times the Moon's distance from earth.

<u>Explanation:</u>

The Earth's distance from the Sun is about 93 million miles. When it expressed in Km, it is 150 million Km.
The Moon's distance from Earth is 238,855 miles. When it is 40 times then it will approximately equal to 93 million miles.
The Sun's distance from Venus is 67.237 million miles. The Sun's distance from mercury is 35.832 million miles.

7 0

4 years ago