The closest would be the Side-Side-Side (SSS) Similarity Theorem, which states that if the lengths of
the corresponding sides of two triangles are proportional, then
the triangles must be similar. But I don't know think that these are actually similar triangles...
Its the second one if I'm not mistaken if not I'm sorry
Answer:
Inequality form: x<1 or x>4
Interval Notation:
(-∞,1)∪(4,∞)
I hope this helps you
The absolutely positively most area that the picture could possibly have is
<em>25.783 square feet</em> (rounded). That would happen if the picture is circular
and the 18-ft goes around its circumference. Then its diameter is 18/pi =
about 5.73 ft and its radius is about 2.865 ft.
If the picture has straight sides, then its greatest possible area is <em>20.25 square ft</em>.
That happens if the picture is square and the 18-ft goes around its perimeter.
Then each side is 4.5-ft.
The area can be as <em><u>small</u></em> as you want, with no limit.
For example,
-- if the picture is 1-ft high and 7-ft wide, and the 18-ft goes
around its perimeter, then its area is <em>7</em> square feet;
-- if the picture is 6-in high and 7-1/2 ft wide, and the 18-ft goes
around its perimeter, then its area is <em>3.75 </em>square feet;
-- if the picture is 1-in high and 8-ft 11-in wide, and the 18-ft goes
around its perimeter, then its area is <em>0.743</em> of a square foot.
Answer:
A. Yes, the two corresponding confidence intervals overlap.
Step-by-step explanation:
The correct option is - A. Yes, the two corresponding confidence intervals overlap.
Reason -
P(1) = 45% = 0.45
E(1) = 4.6% = 0.046
Confidence Interval = P(1) ± E(1)
= 0.45 ± 0.046
So, the interval is -
0.45 + 0.046 ≤ P ≤ 0.45 - 0.046
⇒0.496 ≤ P ≤ 0.404 .............(1)
Now,
P(2) = 42% = 0.42
E(2) = 3.6 % = 0.036
Confidence Interval = P(2) ± E(2)
= 0.42 ± 0.036
So, the interval is -
0.42 + 0.036 ≤ P ≤ 0.42 - 0.036
⇒0.456 ≤ P ≤ 0.384 ...............(2)
From equation (1) and (2), we get
The two corresponding confidence intervals overlap.