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3 years ago

Who can help me?? physic question

Physics

1 answer:

IgorC [24]3 years ago

5 0

Assuming acceleration due to gravity of the moon is constant and there’s no initial velocity in the mans jump we can use one of the kinematic equations. x(final)=x(initial)+(1/2)gt^2. Plug in known values. 0=10-(1.62/2)t^2. The value 1.62 is acceleration of gravity on the moon. Now simply solve for t. t=3.513

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Explanation:

This process is called Bonding and it is done to provide low resistance path to ground.

"Bonding — a low impedance direction achieved by permanently connecting all non-current-carrying metal parts to maintain electrical stability and to be able to conduct any current that is likely to be put on it safely.

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3 years ago

Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star.

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Answer:

The angular speed of the neutron star is 3130.5 rad/s.

Explanation:

Given that,

Initial radius $r_{1}=7\times10^{5}\ km$

Final radius $r_{2}=18 km$

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Equal masses of two stars $m_{1}=m_{2}$

Suppose, If the original star rotated once in 35 days, find the angular speed of the neutron star

Time period of original star T = 35 days = 3024000 s

We need to calculate the initial angular speed of original star

Using formula of angular star

$\omega=\dfrac{2\pi}{T}$

Put the value into the formula

$\omega_{1}=\dfrac{2\pi}{3024000}$

$\omega_{1}=0.00207\times10^{-3}\ rad/s$

Let the initial moment of inertia of the star is

$I_{1}=m_{1}r_{1}^2$

Final moment of inertia of the star is

$I_{2}=m_{2}r_{2}^2$

From the conservation of angular momentum

$I_{1}\omega_{1}=I_{2}\omega_{2}$

$\omega_{2}=\dfrac{I_{1}\omega_{1}}{I_{2}}$

$\omega_{2}=\dfrac{m_{1}r_{1}^2\omega_{1}}{m_{2}r_{2}^2}$

Put the value into the formula

$\omega_{2}=\dfrac{(7.0\times10^{5})^2\times0.00207\times10^{-3}}{18^2}$

$\omega_{2}=3130.5\ rad/s$

Hence, The angular speed of the neutron star is 3130.5 rad/s.

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3 years ago

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Answer:

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Explanation:

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Answer:

The amount of heat transfer is 21,000J .

Explanation:

The equation form of thermodynamics is,

ΔQ=ΔU+W

Here, ΔQ is the heat transferred, ΔU is the change in internal energy, and W is the work done.

Substitute 0 J for W and 0 J for ΔU

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