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qaws [65]
3 years ago
8

What is the temperature of water when baking soda and citric acid is mixed with it?

Chemistry
1 answer:
asambeis [7]3 years ago
4 0

Answer:

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

Explanation:

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

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A solution of KMnO4 has an absorbance of 0.539 when measured in the colorimeter. Determine the concentration of the KMnO4 given
loris [4]

Answer:

Concentration of unknown solution is 0.0416 M

Explanation:

As we know  

Absorbance is equal to the product of molar absorptivity of KMnO4 m, path length and concentration

From the given set of graphical data, it is clear that the absorbance vs concentration is a straight line.  

From the graph, we can obtain-  

Y = 5.73 X – 0.0065

Absorbance = 0.232

0.232 = 5.73 X – 0.0065

X = 0.0416  

Concentration of unknown solution is 0.0416 M

6 0
2 years ago
Indicate the FULL NAME and TOTAL NUMBER of each element in the chemical formula provided. *
REY [17]

Answer:

4 lead  =  Pb

2 nitrogen = N

6 oxygen = O

Explanation:

Know the rules of multiplying wth perentheses.

- Hope that helped! Please let me know if you need further explanation.

6 0
3 years ago
The pressure of 5.00 L of gas increases from 1.50 atm to 1240 mmHg. What is the final volume of the gas, assuming constant tempe
Vsevolod [243]
(P1)(V1)=(P2)(V2)
(1.50)(5.00)=(1240/760)(V2)
(7.5)/(1240/760)=V2
V2=4.596774194 L
5 0
3 years ago
Read 2 more answers
Need help plz help any one
dimulka [17.4K]
Hi!

Composition: the way in which a whole is made up

Hope I helped!
Have a nice day!
6 0
3 years ago
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

6 0
3 years ago
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