Answer:
Odds to be given for an event that either Romance or Downhill wins is 11:4
Explanation:
Given an odd, r = a : b. The probability of the odd, r can be determined by;
Pr(r) =
÷ (
So that;
Odd that Romance will win = 2:3
Pr(R) =
÷ (
=
÷ 
= 
Odd that Downhill will win = 1:2
Pr(D) =
÷ (
=
÷ 
= 
The probability that either Romance or Downhill will win is;
Pr(R) + Pr(D) =
+ 
= 
The probability that neither Romance nor Downhill will win is;
Pr(neither R nor D) = (1 -
)
= 
The odds to be given for an event that either Romance or Downhill wins can be determined by;
= Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)
=
÷ 
= 
Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4
Covalent network. <span>A solid that is extremely hard, that has a very high melting point, and that will not conduct electricity either as a solid or when molten is held together by a continuous three-dimensional network of covalent bonds. Examples include diamond, quartz (SiO </span><span>2 </span>), and silicon carbide (SiC). The electrons are constrained in pairs to a region on a line between the centers of pairs of atoms.<span>
<span /></span>
Answer: a) The concentration after 8.8min is 0.17 M
b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.
Explanation:
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) concentration after 8.8 min:



b) for concentration to decrease from 0.25M to 0.15M


Answer: 1.56 ATM
Explanation: if we assume temperature is constant, gas obeys
Boyles law pV= constant. Then p1·V1= p2·V2. And V1 = p2V2/p1
= 3.0 atm·0,52 l / 1.0 atm