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nlexa [21]
2 years ago
12

What would happen to the sup- ply of ATP in your cells if you did not eat enough carbohydrates? How would this affect your cells

?
Chemistry
1 answer:
harina [27]2 years ago
3 0

Answer:

ATP supply will reduced or decrease drastically

Explanation:

ATP will reduced because carbohydrates are energy given food. Chemical energy are in carbohydrates, therefore when the undergo digestion i.e breakdown of larger pieces into smaller pieces, it is broken down into glucose i.e energy is released. Therefore, if there is now carbohydrates, ATP supply will reduced and there won't be energy needed for different cellular metabolic activities. The breakdown of carbohydrate supply energy.

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A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
Which of the following is the balanced equation for this process?
Hunter-Best [27]
The answer is A.Hope this helps
8 0
3 years ago
How does newton’s third law effect bowling?
Misha Larkins [42]

Answer:

The bowling ball will remain in motion until an unbalanced force acts on the bowling ball. ... When the ball hits the pins, they push on the ball with the same amount of force in the opposite direction. This means that the ball will slow down, and the pins will fall, which is the reaction.

Explanation:

4 0
2 years ago
Read 2 more answers
99 POINTS!! Question: Tell what information each number or symbol in a chemical formula tells you. (Please be specific :)
taurus [48]

Answer: A subscript or superscript is a character that is set slightly below or above the normal line of type, respectively. It is usually smaller than the rest of the text. Subscripts appear at or below the baseline, while superscripts are above.

a coefficient is a constant term related to the properties of a product. In the equation that measures friction, for example, the number that always stays the same is the coefficient.

Parentheses are used in mathematical expressions to denote modifications to normal order of operations (precedence rules). In an expression like , the part of the expression within the parentheses, , is evaluated first, and then this result is used in the rest of the expression.

Chemical symbols are abbreviations used in chemistry for chemical elements, functional groups and chemical compounds. Element symbols for chemical elements normally consist of one or two letters from the Latin alphabet and are written with the first letter capitalized.

That there are no numbers present in the chemical formula means that there is one atom of each element present in the molecule. The Periodic Table reveals that Na is the symbol for sodium, and Cl is the symbol for chlorine.

Explanation:

Is this Good enough?

3 0
3 years ago
Read 2 more answers
Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise
USPshnik [31]

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

Initial:          0.110                  -             -

change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

But final = 0.150atm;

0.110 - 2x    +  4x   +  x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k =  rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3)  t

upon solving, t = 37.1 s

3 0
3 years ago
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