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nlexa [21]
2 years ago
12

What would happen to the sup- ply of ATP in your cells if you did not eat enough carbohydrates? How would this affect your cells

?
Chemistry
1 answer:
harina [27]2 years ago
3 0

Answer:

ATP supply will reduced or decrease drastically

Explanation:

ATP will reduced because carbohydrates are energy given food. Chemical energy are in carbohydrates, therefore when the undergo digestion i.e breakdown of larger pieces into smaller pieces, it is broken down into glucose i.e energy is released. Therefore, if there is now carbohydrates, ATP supply will reduced and there won't be energy needed for different cellular metabolic activities. The breakdown of carbohydrate supply energy.

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If the mass is 44g and the volume is 10ml, what is the density of the object
Helga [31]

Answer:44/10

Explanation:

Because D= G/ml

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3 years ago
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A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2
Mila [183]

From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

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NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

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5 0
1 year ago
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makkiz [27]
A forest would have have the most fertile soil
8 0
2 years ago
Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)&lt;-&gt;Zn2+(aq
Simora [160]

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

8 0
3 years ago
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How many liters of 1.75 M solution could be made using 35 grams of NaCl?
dolphi86 [110]
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
1.75 =  \frac{35}{58.44*V}
1.75*58.44V = 35
102.27V = 35
V =  \frac{35}{102.27}
\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
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