Ask question

Ask question

All categories

2 years ago

15

How many joules of energy are needed to increase the temperature of 60.40 grams of water from 25.0°C to 38.52°C if the specific

heat of water 4.184 J/g°C?

1 answer:

Tanya [424]2 years ago

5 0

Answer:

3416.69J

Explanation:

You might be interested in

Is MgCO3 organic or inorganic

schepotkina [342]

Its inorganic as MgCO3 is contains no carbon more hydrogen which is a crutial component of all organic compounds

4 0

3 years ago

How many grams of chromium are in 2.0 x 1024 atoms

Vaselesa [24]

Answer: 173 g ( 0.17 kg in right accuracy)

Explanation: Amount in moles is n = N/Na = 2.0·10^24 / 6.022·10^23 (1/mol).

n = 3.32116 mol. M(Cr) = 52.00 g/mol and mass m = nM = 172.7 g

7 0

2 years ago

Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Lubov Fominskaja [6]

Answer:

$\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}$

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

$\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}$

4 0

2 years ago

Read 2 more answers

What is landform? please help

KATRIN_1 [288]

Answer:

A landform is a natural or artificial feature of the solid surface of the Earth or other planetary body.

Explanation:

For example, valleys, plateaus, mountains, plains, hills etc.

3 0

2 years ago

Read 2 more answers

A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio

____ [38]

Answer:

Mole fraction: 0,0157.

Molality: 0,889m

Mass%: 16%

Explanation:

<em>The units are mole fraction, molality and mass%</em>

<em />

Units of mole fraction are moles of glucose per total moles.

Moles of glucose assuming 1L are:

0,944 moles.

Moles of water in 1L are:

1L × (1,0624kg/L) × (1000g / 1kg) × (1mol / 18,02g) = <em>59,0 moles of water</em>

<em />

Mole fraction is: 0,944 moles / (59,0 mol + 0,944mol) = <em>0,0157</em>

Molality is mole of solute (0,944) per kg of solution (1,0624kg):

0,944mol / 1,0624kg = <em>0,889m</em>

<em></em>

In mass percent total mass is 1062,4g and mass of 0,944 moles of glucose is:

0,944mol×(180,156g/1mol) = 170g of glucose. Mass%:

170g / 1062,4g ×100 = <em>16%</em>

<em></em>

I hope it helps!

6 0

3 years ago