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ki77a [65]
3 years ago
12

A ball connected to a 1.1 m string and is swing in circular fashion. It’s tangential velocity is 15 m/s. What is its centripetal

acceleration?
Physics
1 answer:
musickatia [10]3 years ago
6 0

Answer:

ac = 204 [m/s²]

Explanation:

To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.

ac = v²/r

where:

v = tangential velocity = 15 [m/s]

r = radius = 1.1 [m]

Now replacing we have:

ac = (15)²/1.1

ac = 204 [m/s²]

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Two forces act on a 1250 kg sailboat as it moves through the water with an initial velocity of 11 m/s. The forward force of the
Naddik [55]

Answer:

The velocity of the boat 15 seconds later is 5.6 meters per second.

Explanation:

We assume that sailboat can be modelled as particle, so that we use solely translations equations. It is noticed that the sailboat is move by action of the wind and drag force of the water is opposed to such force, but the last force has a greater magnitude than the first one, meaning that net force is less than zero.

From Newton's Laws we have the following equation of equilibrium for the sailboat:

\Sigma F = F - f = m\cdot a (Eq. 1)

Where:

F - Force from the wind exerted on the sailboat, measured in newtons.

f - Drag force of the water, measured in newtons.

m - Mass of the sailboat, measured in kilograms.

a - Net acceleration of the sailboat, measured in meters per square second.

If we know that F = 3.90\times 10^{3}\,N, f = 4.35\times 10^{3}\,N and m = 1250\,kg, then the net acceleration of the sailboat is:

a = \frac{F-f}{m}

a = \frac{3.90\times 10^{3}\,N-4.35\times 10^{3}\,N}{1250\,kg}

a = -\frac{9}{25}\,\frac{m}{s^{2}}

If sailboat decelerates uniformly, then we can get the final velocity of the boat by using this equation of motion:

v = v_{o}+a\cdot t (Eq. 2)

Where:

v_{o}, v - Initial and final velocities of the sailboat, measured in meters per second.

t - Time, measured in seconds.

If we get that v_{o} = 11\,\frac{m}{s}, a = -\frac{9}{25}\,\frac{m}{s^{2}} and t = 15\,s, then the final velocity of the sailboat is:

v = 11\,\frac{m}{s} +\left(-\frac{9}{25}\,\frac{m}{s^{2}}  \right)\cdot (15\,s)

v = 5.6\,\frac{m}{s}

The velocity of the boat 15 seconds later is 5.6 meters per second.

3 0
3 years ago
The power of a lens is 4. 0 diopters and its diameter is 5. 0 cm. what is the focal length of this lens?
fenix001 [56]

The focal length of the lens is 25cm

given:

power,p=4 diopters

what is focal length?

Focal length is the distance between the point of convergence of your lens and the sensor or film recording the image.

what is diopter?

The unit of optical power of lens is called diopter.It is the optical power of the lens.

we know,

p=1/f

where,

p= power

f= focal length

f=1/p

f=1/4

=0.25m

=25cm

Thus,the focal length of the lens is 25cm

learn more about focal length from here: https/brainly.com/question/28203589

#SPJ4

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2 years ago
Can somebody help me understand this
Komok [63]
I think it’s C. Marshmallow and toothpicks are used to show the composition of a water molecule
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INK]: A car is moving at 200 km/hr east. What is its velocity?
Greeley [361]

Answer:

200 km\h

or 0.621 mp\h its the same speed just different mesuarements

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A _____ is a quantity that has magnitude and direction
Snezhnost [94]

vector is the answer of this blank

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