Explanation:
(c) I assume we're looking for mA.
Sum of forces on B in the -y direction:
∑F = ma
mBg − T = mBa
Sum of forces on A in the +x direction:
∑F = ma
T = mAa
Substitute:
mBg − mAa = mBa
mBg − mBa = mAa
mA = mB (g − a) / a
Plug in values:
mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))
mA = 495 kg
The answer key seems to have a mistake. It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.
Answer:
5 hours
Explanation:
formula is 6 km per hour
if you have to travel 30 km, divide 30 by 6
30/6 = 5 hours
You should buy a cool camera you never no what a could ,well say you can write a poem of this
Answer:
a) p₀ = 1.2 kg m / s, b) p_f = 1.2 kg m / s, c) θ = 12.36, d) v_{2f} = 1.278 m/s
Explanation:
a system formed by the two balls, which are isolated and the forces during the collision are internal, therefore the moment is conserved
a) the initial impulse is
p₀ = m v₁₀ + 0
p₀ = 0.6 2
p₀ = 1.2 kg m / s
b) as the system is isolated, the moment is conserved so
p_f = 1.2 kg m / s
we define a reference system where the x-axis coincides with the initial movement of the cue ball
we write the final moment for each axis
X axis
p₀ₓ = 1.2 kg m / s
p_{fx} = m v1f cos 20 + m v2f cos θ
p₀ = p_f
1.2 = 0.6 (-0.8) cos 20+ 0.6 v_{2f} cos θ
1.2482 = v_{2f} cos θ
Y axis
p_{oy} = 0
p_{fy} = m v_{1f} sin 20 + m v_{2f} cos θ
0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ
0.2736 = v_{2f} sin θ
we write our system of equations
0.2736 = v_{2f} sin θ
1.2482 = v_{2f} cos θ
divide to solve
0.219 = tan θ
θ = tan⁻¹ 0.21919
θ = 12.36
let's look for speed
0.2736 = v_{2f} sin θ
v_{2f} = 0.2736 / sin 12.36
v_{2f} = 1.278 m / s
Answer:
9.03 x 10³ m /s
Explanation:
magnetic field inside a solenoid
B = μ₀ n I , where μ₀ = 4π X 10⁻⁷ .
n is no of turns per unit length and I is current
so B₁ = 4π x10⁻⁷x 593 / 20.9 x 5.65 x 10²
201.5 x 10⁻⁴ T
B₂ = 4π x 10⁻⁷ x 343 / 19.1 x 1.37 x 10²
= 30.93 x 10⁻⁴ T
Net magnetc field
B₁ -B₂ = B = (201.5 - 30.93) x 10⁻⁴ T
B = 170.57 x 10⁻⁴ T
Now protons move in circular path of radius R in the magnetic field of B
B q v = m v² / R
v = B q R / m
= 170 .57 x 10⁻⁴ x 1.6 x 10⁻¹⁹ x 5.53 x 10⁻³ / (1.67 x 10⁻²⁷)
= 903.71 x 10
= 9.03 x 10³ m /s
=