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Answer:
400 N
Explanation:
Change of Kinetic Energy to Friction Wok
∆KE = W
½ x m x (v(5)² - v(3)²) = f x d
½ x 500 x (5² - 3²) = f x 10
250 x (25 - 9) = f x 10
25 x 16 = f
f = 400 N
A.) For letter a, we use the law of universal gravitation using the constant G = 6.674×10−<span>11 m3</span>⋅kg−1⋅s−<span>2
Grav. F = G*m1*m2*(1/d^2)
m1 is mass of electron = </span>9.11 × 10-31<span> kg
m2 is mass of proton = </span>1.67 × 10<span>-27 kg
d = 4.5 nm = 4.5 x 10^-9 m
Grav F = 5.01 x 10^-51 N
b.) </span>For letter b, we use the Coulomb's using the constant k = 9×10^9 N
Electric force = k*Q1*Q2*(1/d^2)
Q1 is charge of electron = -1.6 × 10-19 C
Q2 is charge of proton = +1.6 × 10-19 C
Electric force = 1.14 x 10^-11 N
The best option for visually representing how one part of data relates
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way to compare and contrast the different parts and how they relate to
one another.
the more pressure put on the string, the more frequency and higher pitch.
