Technician A says the counter gear is actually several gears machined out of a single piece of steel. Technician B says the coun
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Answer:
The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.
Explanation:
Given;
initial velocity of proton, = 3 x 10⁵ m/s
distance moved by the proton, d = 3.5 m
electric field strength, E = 120 N/C
The kinetic energy of the proton at the end of the motion is calculated as follows.
Consider work-energy theorem;
W = ΔK.E
where;
K.Ef is the final kinetic energy
W is work done in moving the proton = F x d = (EQ) x d = EQd
Therefore, the kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.
Answer:
Explanation:
<u>Diagonal Launch </u>
It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.
The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is
Where vo is the magnitude of the initial velocity, is the angle, t is the time and g is the acceleration of gravity
The maximum height the object can reach can be computed as
There are two times where the value of y is when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making
Removing and dividing by t (t different of zero)
Then we find the total flight as
We can easily note the total time (hang time) is twice the maximum (apex) time, so the required time is