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Alborosie
3 years ago
11

Can some please answer these two questions?

Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0

Answer:

1. Mass of potassium (K) = 203.32 g

2. Number of mole of As = 7.53 moles

Explanation:

1. Determination of the mass of potassium (K)

Molar mass of K = 39.1 g/mol

Number of mole of K = 5.2 moles

Mass of K =.?

Mole = mass / Molar mass

5.2 = mass of K / 39.1

Cross multiply

Mass of K = 5.2 × 39.1

Mass of potassium (K) = 203.32 g

2. Determination of the number of mole of Arsenic (As)

Molar mass of As = 74.92 g/mol

Mass of As = 563.9 g

Number of mole of As =.?

Mole = mass /Molar mass

Number of mole of As = 563.9 / 74.92

Number of mole of As = 7.53 moles

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Round to 4 significant figures.<br> 35.5450
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Answer:
35.5450 will be rounded to 35.55
Explanation:
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What is the third alkali metal ​
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A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
Yuri [45]

Answer:

The reaction will continue in the forward direction until all the NO or all the NO₂ is used up.

Explanation:

  • <em>Le Châtelier's principle </em><em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

  • So, according to  Le Chatelier's principle, removing the product (N₂O₃) from the system means decreasing the concentration of the products; thus, the reaction will proceed forward to produce more product to minimize the stress of removing N₂O₃ from the system.

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<em></em>

5 0
3 years ago
An object has a mass of 3.50 grams and a density of 5.61 g/mL. What is the volume of this object? *
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Answer:

<h2>0.62 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{3.50}{5.61}  \\  = 0.6238859...

We have the final answer as

<h3>0.62 mL</h3>

Hope this helps you

5 0
2 years ago
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