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Alborosie
3 years ago
11

Can some please answer these two questions?

Chemistry
1 answer:
alexandr402 [8]3 years ago
8 0

Answer:

1. Mass of potassium (K) = 203.32 g

2. Number of mole of As = 7.53 moles

Explanation:

1. Determination of the mass of potassium (K)

Molar mass of K = 39.1 g/mol

Number of mole of K = 5.2 moles

Mass of K =.?

Mole = mass / Molar mass

5.2 = mass of K / 39.1

Cross multiply

Mass of K = 5.2 × 39.1

Mass of potassium (K) = 203.32 g

2. Determination of the number of mole of Arsenic (As)

Molar mass of As = 74.92 g/mol

Mass of As = 563.9 g

Number of mole of As =.?

Mole = mass /Molar mass

Number of mole of As = 563.9 / 74.92

Number of mole of As = 7.53 moles

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Explanation:

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A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea
Diano4ka-milaya [45]

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

4 0
2 years ago
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Answer:

U= 238g/mol

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Explanation:

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U3O5= 2(238)+3(16)=556g/mol

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3 years ago
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Which is the dependent variable in an experiment? 1.what I observe. 2. what I keep the same 3.What I change in the experiment. H
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Answer:

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