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3 years ago

Which property do liquids and gases share?

Physics

2 answers:

kirza4 [7]3 years ago

8 0

Apparently my answer was deleted. ooof wonder who reported it? it was said that it was correct...

julsineya [31]3 years ago

4 0

C, They change their shapes depending on their containers

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Objects P and Q are placed in a bowl of water. P floats and Q sinks. Which one or more of the following can be deduced from this

Lady bird [3.3K]

The correct option that can be deduced for both Object P and Q is Option b) I and II only

To solve this question correctly, we need to understand the concept of density and it relation to mass and volume.

<h3>What is Density?</h3>

Density is a physical property of an object and can be expressed by using the relation:

$\mathbf{Density = \dfrac{mass}{volume}}$

From the given parameters, we are being told that:

P → floats
Q → sinks

This implies that Q has a greater density that P. Since Q has a greater density than P, Q will be heavier since it will have greater mass.

However, Q will not be denser than water because if that happens, P will be have a greater density which is untrue in this scenario.

Therefore, we can conclude that:

1. Q is heavier than P
II. 1cm³ of Q has a greater mass than 1cm³ of P

Learn more about density here:

brainly.com/question/6838128

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2 years ago

Theories have both an explanatory and a predictive function. <br> a. True <br> b. False

Simora [160]

Theories have both an explanatory an a predictive function. True

3 0

3 years ago

Read 2 more answers

At which point is the kinetic energy the greatest?

mr_godi [17]

Answer:

I don't know

Explanation:

I think it's at the highest, learned this in seventh grade

6 0

3 years ago

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In a series circuit, one of the resistors is replaced with a resistor having a lower resistance value. how does this affect the

Assoli18 [71]

Current will increase.

8 0

3 years ago

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An object is attached to a vertical spring and slowly lowered to its equilibrium position. This stretches the spring by an amoun

trasher [3.6K]

Answer:

Explanation:

For any instance equivalent force acting on the body is

$mg-kd= m\frac{d}{dt}\frac{dx}{dt}$

Where

m is the mass of the object

k is the force constant of the spring

d is the extension in the spring

and

d/dt(dx/dt)= is the acceleration of the object

solving the above equation we get

$x= Asin\omega t +d$

where

$\omega= \sqrt{\frac{k}{m} } = \frac{2\pi}{T}$

A is the amplitude of oscillation from the mean position.

k= spring constant , T= time period

Here we are assuming that at t=T/4

x= 0 since, no extension in the spring

then

A=- d

Hence

x=- d sin wt + d

now, x is maximum when sin wt=- 1

Therefore,

x(maximum)=2d

7 0

3 years ago